java - Java LibGDX在Android上移至触摸位置

我正在使用此代码，但有些并不完美。它正在工作，但不顺利。首先它进入touchX，然后进入touchY。但我同时想要这个。我尝试了不同的代码，但是没有用。我该如何解决？有什么问题？

package com.anil.game1;
import com.badlogic.gdx.ApplicationAdapter;
import com.badlogic.gdx.Gdx;
import com.badlogic.gdx.graphics.GL20;
import com.badlogic.gdx.graphics.OrthographicCamera;
import com.badlogic.gdx.graphics.Texture;
import com.badlogic.gdx.graphics.g2d.SpriteBatch;
import com.badlogic.gdx.math.Rectangle;
import com.badlogic.gdx.math.Vector3;
public class Game1 extends ApplicationAdapter {
    private SpriteBatch batch;
    private OrthographicCamera camera;
    private Texture player1Texture;
    private Rectangle player1Rectangle;
    private Vector3 touchPos;
    @Override
    public void create () {
        batch = new SpriteBatch();
        camera = new OrthographicCamera(480, 800);
        player1Texture = new Texture("Player1.png");
        player1Rectangle = new Rectangle();
        player1Rectangle.set(240, 0, 64, 64);
        touchPos = new Vector3();
    }
    @Override
    public void render () {
        Gdx.gl.glClearColor(0, 0, 0, 1);
        Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);
        batch.setProjectionMatrix(camera.combined);
        batch.begin();
        if (Gdx.input.isTouched()) {
            touchPos.set(Gdx.input.getX(), Gdx.input.getY(), 0);
            camera.unproject(touchPos);
            //player1Rectangle.setPosition(new Vector2(touchPos.x, touchPos.y));
        }
        if (touchPos.x > player1Rectangle.x)
            player1Rectangle.x += 5;
        else
            player1Rectangle.x -= 5;
        if (touchPos.y > player1Rectangle.y)
            player1Rectangle.y += 5;
        else
            player1Rectangle.y -= 5;
        batch.draw(player1Texture, player1Rectangle.x - 32, player1Rectangle.y - 32);
        batch.end();
    }
    @Override
    public void dispose () {
        batch.dispose();
        player1Texture.dispose();
    }
}

最佳答案

在这个部分：

    if (touchPos.x > player1Rectangle.x)
        player1Rectangle.x += 5;
    else
        player1Rectangle.x -= 5;
    if (touchPos.y > player1Rectangle.y)
        player1Rectangle.y += 5;
    else
        player1Rectangle.y -= 5;

您将强制矩形始终沿X和Y方向移动一定的量。永远都不要坐着或放慢脚步。另外，您可能不想分开处理X和Y，因为这样一来，其速度在基本方向上会变慢，在对角线方向上会变快，这看起来很奇怪。最后，您需要在速度和时间上保持稳定的运动速度。

因此，首先，为对象定义速度。另外，您将需要使用Vector2进行计算。

private static final float SPEED = 300f; //world units per second
private final Vector2 tmp = new Vector2();

现在，在计算了触摸位置之后，您想要确定向哪个方向移动以及沿该方向移动多远。因此，在您的isTouched块之后：

//how far the player can move this frame (distance = speed * time):
float maxDistance = SPEED * Gdx.graphics.getDeltaTime();

//a vector from the player to the touch point:
tmp.set(touchPos.x, touchPos.y).sub(player1Rectangle.x, player1Rectangle.y);

if (tmp.len() <= maxDistance) {// close enough to just set the player at the target
    player1Rectangle.x = touchPos.x;
    player1Rectangle.y = touchPos.y;
} else { // need to move along the vector toward the target
    tmp.nor().scl(maxDistance); //reduce vector length to the distance traveled this frame
    player1Rectangle.x += tmp.x; //move rectangle by the vector length
    player1Rectangle.y += tmp.y;
}