我目前有一个球从画布的墙壁上弹起。我在屏幕中间添加了一个矩形。每当球与矩形碰撞时，我也希望球也弹回矩形，但是我不知道该怎么做。我有一个名为“ r”的矩形。
如何使球将矩形视为壁并在碰到矩形时改变方向？代码示例将不胜感激。谢谢。
这是我的球从墙上弹起的代码：
public void handle(ActionEvent t) {
// Moves the ball depending on the values of X and Y
circle.setLayoutX(circle.getLayoutX() + X);
circle.setLayoutY(circle.getLayoutY() + Y);
final Bounds bounds = canvas.getBoundsInLocal();
// Boolean values to check if a wall has been hit
boolean leftWall = circle.getLayoutX() <= (bounds.getMinX() + circle.getRadius());
boolean topWall = circle.getLayoutY() <= (bounds.getMinY() + circle.getRadius());
boolean rightWall = circle.getLayoutX() >= (bounds.getMaxX() - circle.getRadius());
boolean bottomWall = circle.getLayoutY() >= (bounds.getMaxY() - circle.getRadius());
// If the bottom or top wall has been touched, the ball reverses direction.
if (bottomWall || topWall) {
Y = Y * -1;
}
// If the left or right wall has been touched, the ball reverses direction.
if (leftWall || rightWall) {
X = X * -1;
}
}
}));
loop.setCycleCount(Timeline.INDEFINITE);
loop.play();
}
最佳答案
我不知道JavaFx，但这是个主意：
while (1) {
bool btop = pos.y >= top
bool bbottom = pos.y <= bottom
bool bleft = pos.x <= left
bool bright = pos.x >= right
bool rect_btop = pos.y <= rect_top && pos.x >= rect_left && pos.x <= rect_right
bool rect_bbottom = pos.y <= rect_bottom && pos.x >= rect_left && pos.x <= rect_right
bool rect_bright = pos.x <= rect_right && pos.y >= rect_bottom && pos.y <= rect_top
bool rect_bleft = pos.x >= rect_left && pos.y >= rect_bottom && pos.y <= rect_top
if (btop || bottom || rect_btop || rect_bbottom)
vy -= vy
if (bleft || bright || rect_bleft || rect_bright)
vx -= vx
}
但是，还有更好的和可扩展的解决方案（用于编写突破性砖块）。