我有一个可扩展的列表视图。我的一个小组,第一组,有15个孩子。如何在单击并展开Group1时平滑滚动到第10个孩子?
谢谢。
最佳答案
重写适配器的onGroupExpanded
方法并调用其中一个smoothScrollToPosition
方法。类似于:
@Override
public void onGroupExpanded(int groupPosition) {
super.onGroupExpanded(groupPosition);
// If it's the first group
if (groupPosition == 0) {
int scrollTo = groupPosition + 15;
mExpList.smoothScrollToPositionFromTop(scrollTo, 0);
}
}
现在请记住,如果在
ExpandableListView
之前有其他组扩展,groupPosition
将必须考虑到这一点。因此,您可能希望将所有展开的组位置(及其子级计数)保存到一个数组中,并在每次调用scrollTo
和onGroupExpanded
时循环它们。可能是这样的:
@Override
public void onGroupExpanded(int groupPosition) {
super.onGroupExpanded(groupPosition);
groupStates.put(groupPosition, 1);
childrenCount.put(groupPosition, getChildrenCount(groupPosition));
// Loop the group states
int scrollTo = 0;
for (int i=0; i<groupStates.size(); i++) {
int position = groupStates.keyAt(i);
// Cancel the loop if reached a further expanded group
if (position > groupPosition) break;
// 1 is the group to be skipped + its children count
scrollTo += 1 + childrenCount.get(position);
}
// You can select specific child of the recently expanded group, to scroll to
int childToScrollTo = 15; // make sure is an existing child
// -1 because positions begin at index 1
scrollTo = scrollTo - 1 + childToScrollTo;
mExpList.smoothScrollToPositionFromTop(scrollTo, 0);
}
@Override
public void onGroupCollapsed(int groupPosition) {
super.onGroupCollapsed(groupPosition);
groupStates.remove(groupPosition);
childrenCount.remove(groupPosition);
}
但这是未经测试,所以请确保您测试它正确。