c++ - 在C++中为用户定义类型定义输出运算符<<

struct myVals {
        int val1;
        int val2;
    };

    I have static functions

static myVals GetMyVals(void)
{
    // Do some calcaulation.


    myVals  val;
        val.val1 = < calculatoin done in previous value is assigned here>;
        val.val2 = < calculatoin done in previous value is assigned here>;

    return val;
}


bool static GetStringFromMyVals( const myVals& val, char*  pBuffer, int sizeOfBuffer, int   count)
{
    // Do some calcuation.
       char cVal[25];

    // use some calucations and logic to convert val to string and store to cVal;

    strncpy(pBuffer, cVal, count);

    return true;
}

我在这里的要求是，我应该有两个以上的函数要被调用，并使用C++输出运算符(<我们怎样才能做到这一点？我需要新的类(class)来总结一下吗？任何输入都是有帮助的。谢谢

pseudocode:
    operator << () { // operator << is not declared completely
        char abc[30];
        myvals var1 = GetMyVald();
        GetStringFromMyVals(var1, abc, 30, 30);
        // print the string here.
    }

最佳答案

该运算符的签名如下:

std::ostream & operator<<(std::ostream & stream, const myVals & item);

一个实现可能看起来像这样:

std::ostream & operator<<(std::ostream & stream, const myVals & item) {
    stream << item.val1 << " - " << item.val2;
    return stream;
}