我坚持了一段时间,但不确定如何解决此问题。问题是我的SQL查询没有从javaFX文本字段和密码字段获取输入(我正在构建登录窗口)。
如果我手动输入值而不是从文本字段获取值,则程序可以正常运行,否则当您按登录按钮时,什么也不会发生。该问题发生在以下几行中,当然没有错误消息:

 preparedStatement.setString(1,txtUserName.getText());
 preparedStatement.setString(2,txtPassword.getText());


这是完整的代码:

public class LoginWindow implements Initializable{

@FXML
private TextField txtUserName;
@FXML
private PasswordField txtPassword;
@FXML
private Button btnLogin;

Connection connection = null;
PreparedStatement preparedStatement = null;
ResultSet resultSet = null;

// Setting the login button.
@FXML
private void setBtnLogin(ActionEvent event) {
    try {
        connection = DBUtilities.getConnection();
        String sqlQuery = "SELECT * FROM user_login_details WHERE User_Name = ? AND User_Password = ?";
        preparedStatement = connection.prepareStatement(sqlQuery);
        preparedStatement.setString(1,txtUserName.getText());
        preparedStatement.setString(2,txtPassword.getText());
        resultSet = preparedStatement.executeQuery();
        if(resultSet.next()) {
            DBUtilities.showInforMsg("Logged in:", "You have logged in!");

        } else {
            DBUtilities.showErrorMsg("Error:", "Invalid username or password");

        }

    }catch (Exception exception) {
        exception.printStackTrace();

    }finally {
        DBUtilities.closePreparedStatement(preparedStatement);
        DBUtilities.closeResultSet(resultSet);
        DBUtilities.closeConnection(connection);
    }
}
@Override
public void initialize(URL location, ResourceBundle resources) {
    btnLogin.setOnAction(this::setBtnLogin);
}
}

最佳答案

非常感谢你。我只是没有给密码字段提供任何ID。

10-08 12:54