javascript - 我怎样才能使数组与intersects()函数中的对象进行交互？

snake = new Boks(300,300,10,10)

let apple = [];
for(i = 0; i<5; i++){
    let x = random(20,560);
    let y = random(20, 560)
    apple[i] = new Boks(x,y,10,10)
}

for(i = 0; i<apple.length; i++){
    eple[i].visEple();    //a example of how i called the apple object/array
}

if (apple.intersects(snake)){
    background(255,0,0)          //the intersects function
}

intersects(other){
    let di = dist(this.x,this.y,other.x,other.y)
    if (di < this.w) { //this.w is the radius of the apple
        return true;
    } else {
        return false;
    }
}

控制台说apple.intersects不是一个函数，由于某种原因我无法将applet数组与该对象一起使用

最佳答案

控制台说apple.intersects不是一个函数


当然，因为intersects必须是Boks类的方法。您必须将声明移至Boks范围内

class Bocks {

    constructor(x, y, w, h) {

        // [...]
    }

    intersects (other) {
        let di = dist(this.x,this.y,other.x,other.y)
        return di < this.w;
    }
}

该方法必须在类Boks的实例上调用，而不是在数组上调用。例如。：

for (i = 0; i<apple.length; i++){
    if (apple[i].intersect(snake)) {

        // [...]
    }
}

但是请注意，您的交集测试只是测试一个点是否在圆形区域内。
要计算矩形和圆形的交点，请参见Circle-Rectangle collision detection (intersection)。
该算法的Javascript版本：

function intersectCircleRect(circle_x, circle_y, radius, rect_x, rect_y, rect_w, rect_h) {

    // calculate the center of the rectangle
    let rect_cpt_x = rect_x + rect_w/2;
    let rect_cpt_y = rect_y + rect_h/2;

    // calculate the distance of the rectangle center to the circle center
    let dx = abs(circle_x - rect_cpt_x);
    let dy = abs(circle_y - rect_cpt_y);

    // if either dx or dy is greater than the sum of radius half side length, then there is no intersection
    if (dx > rect_w/2 + radius)
        return false;
    if (dy > rect_h/2 + radius)
        return false;

    // if center of circle is in rectangle then there is an intersection
    if (dx <= rect_w/2)
        return true;
    if (dy <= rect_h/2)

    // evaluate intersection by Euclidean distance
    t_dx = dx - rect_w/2;
    t_dy = dy - rect_h/2;
    d_sq = t_dx*t_dx + t_dy*t_dy;
    return d_sq < radius*radius;
}