javascript - Javascript嵌套数组问题

我正在接收以下格式的API JSON数据，并尝试对其进行修改，以便首先按start_date然后按phys_id对其进行分组。我们正在尝试显示约会可用的每个日期，然后显示每个提供者的可用性。

"Today"
      Provider Name #1
             2:20pm
             2:40pm
      Provider Name #2
             1:00pm
             2:40pm
"Tomorrow"
      Provider Name #1
             3:20pm
             4:40pm
      Provider Name #2
             12:00pm
             1:40pm

接收方式如下:

results: [
  {
    start_date: "20191119",
    begintime: "1220",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "035B4177-EF4C-492F-86C8-7157B034DB4A"
  },
  {
    start_date: "20191119",
    begintime: "1400",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "035B4177-EF4C-492F-86C8-7157B034DB4A"
  },
  {
    start_date: "20191119",
    begintime: "1420",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "1ACE5431-2771-40C6-B438-DC8E05701600"
  },
  {
    start_date: "20191119",
    begintime: "1420",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "035B4177-EF4C-492F-86C8-7157B034DB4A"
  },
  {
    start_date: "20191120",
    begintime: "1440",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "035B4177-EF4C-492F-86C8-7157B034DB4A"
  },
  {
    start_date: "20191120",
    begintime: "1600",
    appResourceId: "DB37F253-BA17-4672-8A81-B27388EE57DF",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "1ACE5431-2771-40C6-B438-DC8E05701600"
  },
  {
    start_date: "20191120",
    begintime: "1640",
    appResourceId: "DB37F253-BA17-4672-8A81-B27388EE57DF",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "1ACE5431-2771-40C6-B438-DC8E05701600"
  }
]

我正在使用以下代码将其按start_date分组:

  let group = this.results.reduce((r, a) => {
        r[a.start_date] = [...(r[a.start_date] || []), a];
        return r;
      }, {});
      return group;

然后让我更接近:

{
  "20191119": [
    {
      "start_date": "20191119",
      "begintime": "1220",
      "appResourceId": "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
      "appLocationId": "14A1B866-8393-4510-8144-A45B5C4FD07D",
      "phys_id": "035B4177-EF4C-492F-86C8-7157B034DB4A"
    },
    {
      "start_date": "20191119",
      "begintime": "1400",
      "appResourceId": "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
      "appLocationId": "14A1B866-8393-4510-8144-A45B5C4FD07D",
      "phys_id": "035B4177-EF4C-492F-86C8-7157B034DB4A"
    },
    {
      "start_date": "20191119",
      "begintime": "1420",
      "appResourceId": "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
      "appLocationId": "14A1B866-8393-4510-8144-A45B5C4FD07D",
      "phys_id": "1ACE5431-2771-40C6-B438-DC8E05701600"
    },
    {
      "start_date": "20191119",
      "begintime": "1420",
      "appResourceId": "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
      "appLocationId": "14A1B866-8393-4510-8144-A45B5C4FD07D",
      "phys_id": "035B4177-EF4C-492F-86C8-7157B034DB4A"
    }
  ],
  "20191120": [
    {
      "start_date": "20191120",
      "begintime": "1440",
      "appResourceId": "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
      "appLocationId": "14A1B866-8393-4510-8144-A45B5C4FD07D",
      "phys_id": "035B4177-EF4C-492F-86C8-7157B034DB4A"
    },
    {
      "start_date": "20191120",
      "begintime": "1600",
      "appResourceId": "DB37F253-BA17-4672-8A81-B27388EE57DF",
      "appLocationId": "14A1B866-8393-4510-8144-A45B5C4FD07D",
      "phys_id": "1ACE5431-2771-40C6-B438-DC8E05701600"
    },
    {
      "start_date": "20191120",
      "begintime": "1640",
      "appResourceId": "DB37F253-BA17-4672-8A81-B27388EE57DF",
      "appLocationId": "14A1B866-8393-4510-8144-A45B5C4FD07D",
      "phys_id": "1ACE5431-2771-40C6-B438-DC8E05701600"
    }
  ]
}

有没有一种方法可以使嵌套数组按phys_id分组，以便每个提供程序显示可用的约会时间？还是我会以错误的方式进行操作？

最佳答案

为了优化它，我建议编写一个循环并使用一个普通对象来存储所需的级别。

这是我的示例:

var data = [
  {
    start_date: "20191119",
    begintime: "1220",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "035B4177-EF4C-492F-86C8-7157B034DB4A"
  },
  {
    start_date: "20191119",
    begintime: "1400",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "035B4177-EF4C-492F-86C8-7157B034DB4A"
  },
  {
    start_date: "20191119",
    begintime: "1420",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "1ACE5431-2771-40C6-B438-DC8E05701600"
  },
  {
    start_date: "20191119",
    begintime: "1420",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "035B4177-EF4C-492F-86C8-7157B034DB4A"
  },
  {
    start_date: "20191120",
    begintime: "1440",
    appResourceId: "DAD6C44B-3CAC-4BDA-A485-F4BB033FA928",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "035B4177-EF4C-492F-86C8-7157B034DB4A"
  },
  {
    start_date: "20191120",
    begintime: "1600",
    appResourceId: "DB37F253-BA17-4672-8A81-B27388EE57DF",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "1ACE5431-2771-40C6-B438-DC8E05701600"
  },
  {
    start_date: "20191120",
    begintime: "1640",
    appResourceId: "DB37F253-BA17-4672-8A81-B27388EE57DF",
    appLocationId: "14A1B866-8393-4510-8144-A45B5C4FD07D",
    phys_id: "1ACE5431-2771-40C6-B438-DC8E05701600"
  }
]


const group = {};

for (const datum of data) {
    const date = datum.start_date;
    const pId = datum.phys_id;

    if (!group[date]) {
        group[date] = {};
    }

    if (!group[date][pId]) {
        group[date][pId] = [];
    }

    group[date][pId].push(datum);
}


console.log(group);