我有三个表,其结构如下(它们在mysql数据库中)通过雄辩的模型连接到我的laravel 5 api:
# build_sets table
| id | title | description |
# parts table
| id | title | description | color |
# build_set_parts table
| id | build_set_id | part_id | amount | special_info |
现在我做这样的查询:
$buildSets = array();
foreach(BuildSet::with('parts')->get() as $buildSet) {
$temp = json_decode($buildSet);
$temp->parts = $buildSet->parts;
$buildSets[] = $temp;
}
return $buildSets;
我的模特看起来是这样的:
class BuildSet extends Model
{
protected $table = 'build_sets';
protected $hidden = ['created_at', 'updated_at'];
public function parts()
{
return $this->hasMany('App\Models\BuildSetPart');
}
}
class Part extends Model
{
protected $table = 'parts';
protected $hidden = ['id', 'created_at', 'updated_at'];
public function buildSets()
{
return $this->hasMany('App\Models\BuildSet');
}
}
class BuildSetPart extends Model
{
protected $table = 'build_set_parts';
protected $hidden = ['id', 'build_set_id', 'part_id', 'created_at', 'updated_at'];
public function buildSet()
{
return $this->belongsTo('App\Models\BuildSet');
}
public function part()
{
return $this->belongsTo('App\Models\Part');
}
}
我得到这样的结果(json响应):
[
{
"id": 1,
"title": "Build set 1",
"description": "This is a small build set.",
"parts": [
{
"amount": 150,
"special_info": ""
},
{
"amount": 400,
"special_info": "Extra strong"
},
{
"amount": 25,
"special_info": ""
}
]
},
{
"id": 2,
"title": "Build set 2",
"description": "This is a medium build set.",
"parts": [
{
"amount": 150,
"special_info": ""
},
{
"amount": 400,
"special_info": "Extra strong"
},
{
"amount": 25,
"special_info": ""
},
{
"amount": 25,
"special_info": ""
},
{
"amount": 25,
"special_info": ""
}
]
}
]
如您所见,我在构建集中包含的“parts”数组中缺少标题、描述和颜色。
所以我的问题是,如何在我的回答中添加标题和颜色?我可以通过使用雄辩的模型来实现这一点吗,或者我必须在获取所有构建集的地方创建自己的db查询,然后迭代它们,获取所有部分和构建集部分,然后合并结果并将其添加到构建集。
任何人都有一个很好的解决方案,它将为我提供如下格式的零件数组中的项:
[
{
"title": "Part 1",
"color": "Red",
"amount": 25,
"special_info": ""
},
{
"title": "Part 2",
"color": "Green",
"amount": 75,
"special_info": ""
}
]
最佳答案
从你的模型中,你得到了BuildSet
和Part
之间的多对多关系。
因此,在BuildSet
中,可以使用hasManyThrough
关系。
型号BuildSet
public function parts()
{
return $this->hasManyThrough('App\Models\Part', 'App\Models\BuildSetPart');
}
来源:http://laravel.com/docs/5.0/eloquent#relationships
无论如何,如果你想保持
BuildSet
和BuildSetPart
之间的关系。我建议你改用这个。
public function buildSetPart()
{
return $this->hasMany('App\Models\BuildSetPart');
}
注意:现在,您在
parts()
模型中同时得到buildSetPart()
和BuildSet
。创建关系后,可以替换代码
$buildSets = array();
foreach(BuildSet::with('parts')->get() as $buildSet) {
$temp = json_decode($buildSet);
$temp->parts = $buildSet->parts;
$buildSets[] = $temp;
}
return $buildSets;
具有
return BuildSet::with('parts')->get();
或者,如果您想要json格式的输出
return BuildSet::with('parts')->toJson();
来源:http://laravel.com/docs/5.0/eloquent#collections