我已经看到类似的问题,并尝试了解决方案,但对它们的答案似乎没有用。我有以下代码:
.h
#include <iostream>
#include <vector>
#include <string>
using std::string; using std::vector;
struct DialogueNode;
struct DialogueOption {
string text;
DialogueNode *next_node;
int return_code;
DialogueOption(string t, int rc, DialogueNode * nn) : text{t},
return_code{rc}, next_node{nn} {}
};
struct DialogueNode {
string text;
vector <DialogueOption> dialogue_options;
DialogueNode();
DialogueNode(const string &);
};
struct DialogueTree {
DialogueTree() {}
void init();
void destroyTree();
int performDialogue();
private:
vector <DialogueNode*> dialogue_nodes;
};
.cpp
#include "dialogue_tree.h"
DialogueNode::DialogueNode(const string &t) : text{t} {}
void DialogueTree::init() {
string s = "Hello";
for(int i = 0; i < 5; i++) {
DialogueNode *node = new DialogueNode(s);
dialogue_nodes.push_back(node);
delete node;
}
}
void DialogueTree::destroyTree() {
}
int DialogueTree::performDialogue() {
return 0;
}
int main() {
return 0;
}
我收到错误:
error: no matching function for call to ‘DialogueNode:: DialogueNode(std::__cxx11::string&)’ DialogueNode *node = new DialogueNode(s);
编辑有关错误的其他说明
dialogue_tree.h:17:8: note: candidate: DialogueNode::DialogueNode()
dialogue_tree.h:17:8: note: candidate expects 0 arguments, 1 provided
dialogue_tree.h:17:8: note: candidate: DialogueNode::DialogueNode(const DialogueNode&)
dialogue_tree.h:17:8: note: no known conversion for argument 1 from ‘std::__cxx11::string {aka std::__cxx11::basic_string<char>}’ to ‘const DialogueNode&’
dialogue_tree.h:17:8: note: candidate: DialogueNode::DialogueNode(DialogueNode&&)
dialogue_tree.h:17:8: note: no known conversion for argument 1 from ‘std::__cxx11::string {aka std::__cxx11::basic_string<char>}’ to ‘DialogueNode&&’
这对我来说毫无意义,因为我已定义了构造函数以
string
作为参数。 最佳答案
您已将构造函数声明为:
DialogueNode(const string);
但将其定义为:
DialogueNode(const string &t);
那两个是不一样的。前者采用
const string
,而后者采用const string
引用。您必须添加&
来指定引用参数:DialogueNode(const string &);