我做了一个使用spring + hibernate(JPA映射)的项目。我正在使用一对多JPA Hibernate。我不知道我的设计本身是错的还是什么。我有两个班级Useradmin(父母)和Tanya(孩子)。从这,我需要通过使用Useradmin(父级)的属性从另一个表中获取记录。当我为Tanya(孩子)插入新记录时,Useradmin(父母)也更新了。我只想插入Tanya(子级),插入或更新Useradmin(父级)。任何人都可以给我解决方案,请提出建议继续进行:)
这是我的Useradmin类别:
@SuppressWarnings("serial")
@Entity
@Table(name="user")
public class UserAdmin implements Serializable{
@Id
@Column(name="no_dana", unique=true, nullable=false, updatable=false)
private String no_dana;
@Column(name="npp")
private String npp;
@Column(name="password")
private String password;
@Column(name="nama_depan")
private String nama_depan;
@Column(name="nama_tengah")
private String nama_tengah;
@Column(name="nama_belakang")
private String nama_belakang;
@Column(name="kota")
private String kota;
@OneToMany(cascade=CascadeType.ALL, mappedBy="useradmin")
private Set<Tanya> tanya = new HashSet<Tanya>(0);
/**other field**//
/**setter and gettter methods**/
}
这是我的Tanya课:
@SuppressWarnings("serial")
@Entity
@Table(name="tanya")
public class Tanya implements Serializable{
@Id
@Column(name="id_tanya", unique=true, nullable=false)
private int id_tanya;
@Column(name="subject")
private String subject;
@Column(name="isi")
private String isi;
@Temporal(TemporalType.TIMESTAMP)
@Column(name="created")
private Date created;
@ManyToOne(cascade=CascadeType.ALL)
@JoinColumn(name="no_dana")
private UserAdmin useradmin;
/**other field**//
/**setter and gettter methods**/
}
这是我的控制器:
@RequestMapping("/user/tanya-jawab.html")
public ModelAndView listTanyaJawab(ModelMap model)throws Exception
{
User user = (User)SecurityContextHolder.getContext().getAuthentication().getPrincipal();
String sessionUser = user.getUsername();
try{
UserAdmin dataUser = userService.get(sessionUser);
model.addAttribute("userData", dataUser);
} catch(Exception e){
e.printStackTrace();
}
ModelAndView mav = new ModelAndView("usr-tanya");
List<Tanya> tanyajawab = tanyaService.listAllTanya();
mav.addObject("tanyajawab", tanyajawab);
return mav;
}
@RequestMapping(value="/user/add-tanya-jawab.html", method=RequestMethod.POST)
public ModelAndView addTanyaJawab(@ModelAttribute Tanya tanya, ModelMap model, HttpServletRequest request, HttpServletResponse response)throws Exception
{
String userName = request.getParameter("hiddenUsername");
UserAdmin useradmin = new UserAdmin();
useradmin.setNo_dana(userName);
System.out.println("ini"+userName);
java.util.Date date = new java.util.Date();
tanya.setUseradmin(useradmin);
tanya.setCreated(date);
tanyaService.save(tanya);
return listTanyaJawab(model);
}
任何帮助将是荣幸:)
最佳答案
如果我正确理解了此问题,则可能是您的
public ModelAndView addTanyaJawab(@ModelAttribute Tanya tanya, ModelMap model, HttpServletRequest request, HttpServletResponse response)throws Exception {...}
方法。您正在使用以下命令创建一个新的Useradmin对象:
UserAdmin useradmin = new UserAdmin();
问题在于该对象是新对象,尚未持久到数据库中。创建新的Tanya对象时,会将其引用到新的UserAdmin对象。但是,这不存在。
您需要在已从数据库中预先加载的Tanya对象中设置永久性UserAdmin对象,或者创建一个新的UserAdmin对象,添加Tanya并保存该对象。