我做了一个使用spring + hibernate(JPA映射)的项目。我正在使用一对多JPA Hibernate。我不知道我的设计本身是错的还是什么。我有两个班级Useradmin(父母)和Tanya(孩子)。从这,我需要通过使用Useradmin(父级)的属性从另一个表中获取记录。当我为Tanya(孩子)插入新记录时,Useradmin(父母)也更新了。我只想插入Tanya(子级),插入或更新Useradmin(父级)。任何人都可以给我解决方案,请提出建议继续进行:)

这是我的Useradmin类别:

@SuppressWarnings("serial")
@Entity
@Table(name="user")
public class UserAdmin implements Serializable{

@Id
@Column(name="no_dana", unique=true, nullable=false, updatable=false)
private String no_dana;

@Column(name="npp")
private String npp;

@Column(name="password")
private String password;

@Column(name="nama_depan")
private String nama_depan;

@Column(name="nama_tengah")
private String nama_tengah;

@Column(name="nama_belakang")
private String nama_belakang;

@Column(name="kota")
private String kota;

@OneToMany(cascade=CascadeType.ALL, mappedBy="useradmin")
private Set<Tanya> tanya  = new HashSet<Tanya>(0);

/**other field**//

/**setter and gettter methods**/
}


这是我的Tanya课:

@SuppressWarnings("serial")
@Entity
@Table(name="tanya")
public class Tanya implements Serializable{

@Id
@Column(name="id_tanya", unique=true, nullable=false)
private int id_tanya;

@Column(name="subject")
private String subject;

@Column(name="isi")
private String isi;

@Temporal(TemporalType.TIMESTAMP)
@Column(name="created")
private Date created;

@ManyToOne(cascade=CascadeType.ALL)
@JoinColumn(name="no_dana")
private UserAdmin useradmin;

/**other field**//

/**setter and gettter methods**/
}


这是我的控制器:

@RequestMapping("/user/tanya-jawab.html")
public ModelAndView listTanyaJawab(ModelMap model)throws Exception
{
    User user           = (User)SecurityContextHolder.getContext().getAuthentication().getPrincipal();
    String sessionUser  = user.getUsername();

    try{
        UserAdmin dataUser = userService.get(sessionUser);
        model.addAttribute("userData", dataUser);
    } catch(Exception e){
        e.printStackTrace();
    }

    ModelAndView mav = new ModelAndView("usr-tanya");
    List<Tanya> tanyajawab = tanyaService.listAllTanya();
    mav.addObject("tanyajawab", tanyajawab);
    return mav;
}

@RequestMapping(value="/user/add-tanya-jawab.html", method=RequestMethod.POST)
public ModelAndView addTanyaJawab(@ModelAttribute Tanya tanya, ModelMap model, HttpServletRequest request, HttpServletResponse response)throws Exception
{
    String userName = request.getParameter("hiddenUsername");

    UserAdmin useradmin = new UserAdmin();
    useradmin.setNo_dana(userName);
    System.out.println("ini"+userName);
    java.util.Date date = new java.util.Date();

    tanya.setUseradmin(useradmin);
    tanya.setCreated(date);
    tanyaService.save(tanya);

    return listTanyaJawab(model);
}


任何帮助将是荣幸:)

最佳答案

如果我正确理解了此问题,则可能是您的

public ModelAndView addTanyaJawab(@ModelAttribute Tanya tanya, ModelMap model, HttpServletRequest request, HttpServletResponse response)throws Exception {...}


方法。您正在使用以下命令创建一个新的Useradmin对象:

    UserAdmin useradmin = new UserAdmin();


问题在于该对象是新对象,尚未持久到数据库中。创建新的Tanya对象时,会将其引用到新的UserAdmin对象。但是,这不存在。

您需要在已从数据库中预先加载的Tanya对象中设置永久性UserAdmin对象,或者创建一个新的UserAdmin对象,添加Tanya并保存该对象。

09-06 08:40