c++ - C++保留对象列表并通过另一个函数调用构造函数

为什么不创建我的对象？
以及如何从构造函数中执行AllReferrals.push_back(this);？

当我这样做的时候，我被告知


  错误C2065：“ AllReferrals”：未声明的标识符


以及


  错误C2228：“。push_back”的左侧必须具有class / struct / union


如果我将列表初始化放在类之前


  错误C2065：“ AllReferrals”：未声明的标识符


这是我的代码：

class Referral
{
public:
    string url;
    map<string, int> keywords;

    static bool submit(string url, string keyword, int occurrences)
    {
        //if(lots of things i'll later add){
        Referral(url, keyword, occurrences);
        return true;
        //}
        //else
        //    return false;
    }

private:
    list<string> urls;

    Referral(string url, string keyword, int occurrences)
    {
        url = url;
        keywords[keyword] = occurrences;
        AllReferrals.push_back(this);
    }
};

static list<Referral> AllReferrals;

int main()
{
    Referral::submit("url", "keyword", 1);
}

最佳答案

当您从上至下读取文件时，必须在使用AllReferrals名称之前对其进行声明。

如果未声明，则编译器不知道它存在。这就是错误的意思。

要解决您的问题，只需在使用声明之前移动声明，然后为需要名称但尚未定义的类型使用“转发声明”。

#include <iostream>
#include <fstream>
#include <regex>
#include <string>
#include <list>
#include <map>

using namespace std;
using namespace tr1;

class Referral; // forward declaration
list<Referral> AllReferrals; // here 'static' is not needed

class Referral
{
public:
 string url;
 map<string, int> keywords;

 static bool submit(string url, string keyword, int occurrences)
 {
  //if(lots of things i'll later add){
   Referral(url, keyword, occurrences);
   return true;
  //}
  //else
  // return false;
 }

private:
 list<string> urls;

 Referral(string url, string keyword, int occurrences)
 {
  url = url;
  keywords[keyword] = occurrences;
  AllReferrals.push_back(this);
 }
};


int main()
{
 Referral::submit("url", "keyword", 1);
 cout << AllReferrals.size();
 cout << "\n why does that ^^ say 0  (help me make it say one)?";
 cout << "\n and how can i AllReferrals.push_back(this) from my constructor?";
 cout << " When I do it like so, I am told  error C2065: 'AllReferrals' : undeclared identifier";
 cout << " as well as error C2228: left of '.push_back' must have class/struct/union.";
 cout << " If I put the list initialization before the class I get error C2065: 'AllReferrals' : undeclared identifier.";
 cout << "\n\n\t Thanks!";
 getchar();
}

正如评论者所添加的，另一种解决方案是将构造函数定义移到AllReferrals定义下。
无论如何，这始终是名称分配命令的问题。