Java学习总结8

完成火车站售票程序的模拟。

要求:

(1) 总票数1000张;

(2) 10个窗口同时开始卖票;

(3) 卖票过程延时1秒钟;

(4)不能出现一票多卖或卖出负数号票的情况。

实验代码：

package com.cissst.software.synthread;

public class MainThread {
    public static void main(String[] args) {
        MyThread sicket=new MyThread();
        Thread t1 = new Thread(sicket,"窗口一");
        Thread t2 = new Thread(sicket,"窗口二");
        Thread t3 = new Thread(sicket,"窗口三");
        Thread t4 = new Thread(sicket,"窗口四");
        Thread t5 = new Thread(sicket,"窗口五");
        Thread t6 = new Thread(sicket,"窗口六");
        Thread t7= new Thread(sicket,"窗口七");
        Thread t8 = new Thread(sicket,"窗口八");
        Thread t9 = new Thread(sicket,"窗口九");
        Thread t10 = new Thread(sicket,"窗口十");
        t1.start();
        t2.start();
        t3.start();
        t4.start();
        t5.start();
        t6.start();
        t7.start();
        t8.start();
        t9.start();
        t10.start();
    }
}
package com.cissst.software.synthread;
class MyThread implements Runnable {
        private int count = 1000;
        Object lock = new Object();
        @Override
        public void run() {
            while(count > 0){
                try {
                    Thread.sleep(1000);
                } catch (InterruptedException e) {
// TODO Auto-generated catch block
                    e.printStackTrace();
                }
                synchronized(lock){
                    if(count > 0){
                        System.out.println(Thread.currentThread().getName()+"正在售第" + count + "张车票");    //售完一张车票，剩余总票数减一
                        count --;
                    }
                }
            }
        }
    }

实验结果：