我正在尝试创建一个记事本应用程序,该应用程序在顶部具有三个选项卡,每个选项卡都链接到一个不同的视图。
前两个选项卡仅包含一个要填写的表格,而第三个选项卡则是实际书写的地方。问题是,每当我尝试扩大第三个视图时,此行都会出现空指针异常:
((LinearLayout) findViewById(R.id.drawRoot)).addView(v,0);
这是我的代码:
public void onTabSelected(ActionBar.Tab tab, FragmentTransaction fragmentTransaction) {
// When the given tab is selected, show the tab contents in the container
Fragment fragment = new Section3Fragment();
Bundle args = new Bundle();
args.putInt(Section3Fragment.ARG_SECTION_NUMBER, tab.getPosition() + 1);
fragment.setArguments(args);
getSupportFragmentManager().beginTransaction()
.replace(R.id.container3, fragment)
.commit();
}
public void onTabReselected(ActionBar.Tab tab, FragmentTransaction fragmentTransaction) {
}
public class Section3Fragment extends Fragment {
public Section3Fragment() {
}
int section;
public static final String ARG_SECTION_NUMBER = "section_number";
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
Bundle args = getArguments();
section = args.getInt(ARG_SECTION_NUMBER);
View view;
if (section == 1)
{
view = inflater.inflate(R.layout.section3_page1, container,false);
return view;
}
if (section == 2){
view = inflater.inflate(R.layout.section3_page2, container, false);
return view;
}
else {
if(v != null)
Log.v("not null", "not null");
view = inflater.inflate(R.layout.section3_page3, container, false);
((LinearLayout) findViewById(R.id.drawRoot)).addView(v,0); //null pointer exception here!!
return view;
}
}
}
对象v是我用来进行实际绘制的类的实例。
和section3_page3布局文件
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/drawRoot"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
</LinearLayout>
任何对此问题的见解,我们将不胜感激。
最佳答案
乍一看,您是否要这样做:
((LinearLayout) view.findViewById(R.id.drawRoot)).addView(v,0);
您正在寻找片段的视图。不在if语句中夸大的视图上。