我想使用Java中的JAXB反序列化XML,如下所示:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<container>
inner text that I need
<foo attrib="meh">
<bar>value</bar>
</foo>
</container>
</root>
让我大跌眼镜的是捕获
<container>
的内部文本:我不能同时使用@XmlValue
获取内部文本和@XmlElement
来获取内部文本之后的foo元素。请参阅下文,了解我要做什么import java.io.ByteArrayInputStream;
import java.io.UnsupportedEncodingException;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlValue;
import javax.xml.stream.XMLEventReader;
import javax.xml.stream.XMLInputFactory;
import javax.xml.stream.XMLStreamException;
import javax.xml.stream.events.XMLEvent;
public class App {
private static final String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><root><container>text<foo attrib=\"meh\"><bar>waffles</bar></foo></container></root>";
@XmlRootElement(name = "foo") static class Foo {
@XmlAttribute public String attrib;
@XmlElement public String bar;
}
@XmlRootElement(name = "container") static class Container {
//@XmlValue public String innerText;
@XmlElement public Foo foo;
}
public static void main(String[] args) {
try {
final XMLInputFactory xmlInputFactory = XMLInputFactory.newInstance();
final XMLEventReader xer = xmlInputFactory.createXMLEventReader(new ByteArrayInputStream(xml.getBytes("UTF-8")));
XMLEvent evt = xer.nextEvent(); // start document
evt = xer.nextEvent(); // <root>
evt = xer.peek(); // advance to <container>
JAXBContext ctx = JAXBContext.newInstance(Container.class);
Unmarshaller um = ctx.createUnmarshaller();
Object o = um.unmarshal(xer);
} catch (UnsupportedEncodingException ex) {
Logger.getLogger(App.class.getName()).log(Level.SEVERE, null, ex);
} catch (XMLStreamException ex) {
Logger.getLogger(App.class.getName()).log(Level.SEVERE, null, ex);
} catch (JAXBException ex) {
Logger.getLogger(App.class.getName()).log(Level.SEVERE, null, ex);
}
}
}
最佳答案
这称为“混合模式内容”,通常很难处理。
JAXB的关键是使用@XmlMixed
批注-请参见javadoc。
尝试这样的事情:
@XmlRootElement(name = "container")
static class Container {
@XmlMixed
@XmlElementRefs({
@XmlElementRef(name="foo", type=Foo.class)
})
List<?> content;
// ... plus the usual getters/setters
}
content
列表应包含Foo
对象和字符串的序列。