下面是一些Python代码,我编写这些代码是为了生成一个随机的扑克手,只是为了应付这个挑战,但是当我尝试运行它时,我在上面的“if card in hand”行中得到了错误。?
import random
def pokerHand():
hand = ["This is your hand:"]
x = 0
while x < 5:
cardNum = random.randrange(13) + 1
if cardNum == 1:
cardNum = "Ace of "
elif cardNum == 11:
cardNum = "Jack of "
elif cardNum == 13:
cardNum = "King of "
elif cardNum == 12:
cardNum = "Queen of "
else:
cardNum = str(cardNum) + " of "
cardSuit = random.randrange(4)
if cardSuit == 0:
cardSuit = "Clubs"
elif cardSuit == 1:
cardSuit = "Diamonds"
elif cardSuit == 3:
cardSuit = "Hearts"
elif cardSuit == 2:
cardSuit = "Spades"
card = cardNum + cardSuit
if card in hand: #<the line of error
pass
else:
hand = hand.append(card)
x = x + 1
for xx in hand:
print xx
最佳答案
hand = hand.append(card)
append
不返回任何内容。更改为:hand.append(card)