我从sourceImage中提取了四个角:
src_vertices[0] = corners[upperLeft];
src_vertices[1] = corners[upperRight];
src_vertices[2] = corners[downLeft];
src_vertices[3] = corners[downRight];
这四个角将像这样扭曲到destinationImage:
dst_vertices[0] = Point(0,0);
dst_vertices[1] = Point(width, 0);
dst_vertices[2] = Point(0, height);
dst_vertices[3] = Point(width, height);
Mat warpPerspectiveMatrix = getPerspectiveTransform(src_vertices, dst_vertices);
cv::Size size_d = Size(width, height);
cv::Mat DestinationImage(width,height,CV_8UC3);
warpPerspective(sourceImage, destinationImage, warpPerspectiveMatrix, size_d, INTER_LINEAR, BORDER_CONSTANT);
现在我的问题是:
我有一个从destinationImage取得的点p(x,y),如何在原始sourceImage中检索此点的坐标
换句话说,我想使用warpPerspectiveMatrix来完成getPerspectiveTransform的相反工作
最佳答案
您需要逆透视变换。如果原始转换为S-> S',则需要转换矩阵S'-> S
Mat InversewarpPerspectiveMatrix = getPerspectiveTransform(dst_vertices, src_vertices);
然后制作一个SPARSE矩阵
Mat PerspectiveCoordinates containing the vector x,y.
最后你要打电话
PerspectiveTransform(PerspectiveCoordinates,OriginalCoordinates,InversewarpPerspectiveMatrix)