我有一个可以将JSONObject放入一个编辑文本的项目，但是我试图弄清楚如何对其进行更改，以便它可以将JSONArray放入一个listView中。
这是我当前的代码：
public class Js extends Activity {
private String url1 = "http://api.openweathermap.org/data/2.5/weather?q=chicago";
//private String url1 = "http://bisonsoftware.us/hhs/messages.json";
private TextView temperature;//,country,temperature,humidity,pressure;
private HandleJSON obj;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_js);
//location = (EditText)findViewById(R.id.editText1);
//country = (TextView)findViewById(R.id.editText2);
temperature = (TextView)findViewById(R.id.editText3);
//humidity = (EditText)findViewById(R.id.editText4);
//pressure = (EditText)findViewById(R.id.editText5);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items
//to the action bar if it is present.
getMenuInflater().inflate(R.menu.js, menu);
return true;
}
public void open(View view){
//String url = location.getText().toString();
//String finalUrl = url1 + url;
//country.setText(url1);
obj = new HandleJSON(url1);
obj.fetchJSON();
while(obj.parsingComplete);
//country.setText(obj.getCountry());
temperature.setText(obj.getTemperature());
//humidity.setText(obj.getHumidity());
//pressure.setText(obj.getPressure());
}
}
public class HandleJSON {
//private String country = "temperature";
private String temperature = "clouds";
//private String humidity = "humidity";
//private String pressure = "pressure";
private String urlString = null;
public volatile boolean parsingComplete = true;
public HandleJSON(String url){
this.urlString = url;
}
/*public String getCountry(){
return country;
}*/
public String getTemperature(){
return temperature;
}
/*public String getHumidity(){
return humidity;
}
public String getPressure(){
return pressure;
}*/
@SuppressLint("NewApi")
public void readAndParseJSON(String in) {
try {
JSONObject reader = new JSONObject(in);
//JSONObject sys = reader.getJSONObject("main");
//country = sys.getString("temp");
JSONObject main = reader.getJSONObject("clouds");
temperature = main.getString("all");
//pressure = main.getString("pressure");
//humidity = main.getString("humidity");
parsingComplete = false;
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public void fetchJSON(){
Thread thread = new Thread(new Runnable(){
@Override
public void run() {
try {
URL url = new URL(urlString);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(10000 /* milliseconds */);
conn.setConnectTimeout(15000 /* milliseconds */);
conn.setRequestMethod("GET");
conn.setDoInput(true);
// Starts the query
conn.connect();
InputStream stream = conn.getInputStream();
String data = convertStreamToString(stream);
readAndParseJSON(data);
stream.close();
} catch (Exception e) {
e.printStackTrace();
}
}
});
thread.start();
}
static String convertStreamToString(java.io.InputStream is) {
java.util.Scanner s = new java.util.Scanner(is).useDelimiter("\\A");
return s.hasNext() ? s.next() : "";
}
}
我已经尝试了一段时间，但是找不到解析数据的好方法。在此先感谢您提供的任何帮助。
这是JSON：
"messages":["This is a demo message. Enjoy!","Another demonstration message stored in JSON format.","JSON stands for JavaScript Object Notation (I think)"]
最佳答案
您真正要问的是几个问题。自己动手，我想您会轻松得多。
创建执行互联网服务请求并返回响应，处理错误情况等的功能。
创建一个反映JSON内容的“天气”类（例如，针对您的类，包含温度，压力，湿度等的类）
创建检查响应的有效性并从中构造Weather对象的功能。
从响应中创建这些天气对象（列表，集合等）的集合
创建一个自定义ListAdapter，它接受Weather对象的实例并将其转换为UI。
???
利润
单独考虑，您将可以更轻松地解决此问题。自定义适配器很容易实现。因此，假设您有一个简单的Weather类，如下所示：
public final class Weather {
public final String temperature;
public final String pressure;
public final String humidity;
public Weather(String temperature, String pressure, String humidity) {
this.temperature = temperature;
this.pressure = pressure;
this.humidity = humidity;
}
public static Weather valueOf(JSONObject json) throws JSONException {
String temperature = json.getString("temp");
String pressure = json.getString("pressure");
String humidity = json.getString("humidity");
}
}
创建一个简单的
BaseAdapter子类，该子类将您的Weather修改为您创建的自定义布局：public final class WeatherAdapter extends BaseAdapter {
private final List<Weather> mWeatherList;
private final LayoutInflater mInflater;
public WeatherAdapter(Context ctx, Collection<Weather> weather) {
mInflater = LayoutInflater.from(ctx);
mWeatherList = new ArrayList<>();
mWeatherList.addAll(weather);
}
@Override public int getCount() {
// Return the size of the data set
return mWeatherList.size();
}
@Override public Weather getItem(int position) {
// Return the item in our data set at the given position
return mWeatherList.get(position);
}
@Override public long getItemId(int position) {
// Not useful in our case; just return position
return position;
}
@Override public View getView(int position, View convertView, ViewGroup parent) {
if (convertView == null) {
// There's no View to re-use, inflate a new one.
// This assumes you've created a layout "weather_list_item.xml"
// with textviews for pressure, temperature, and humidity
convertView = mInflater.inflate(R.layout.weather_list_item, parent, false);
// Cache the Views we get with findViewById() for efficiency
convertView.setTag(new WeatherViewHolder(convertView));
}
// Get the weather item for this list position
Weather weather = getItem(position);
WeatherViewHolder holder = (WeatherViewHolder) convertView.getTag();
// Assign text, icons, etc. to your layout
holder.pressure.setText(weather.pressure);
holder.temperature.setText(weather.temperature);
holder.humidity.setText(weather.humidity);
return convertView;
}
public static class WeatherViewHolder {
public final TextView pressure;
public final TextView humidity;
public final TextView temperature;
public WeatherViewHolder(View v) {
pressure = (TextView) v.findViewById(R.id.pressure);
humidity = (TextView) v.findViewById(R.id.humidity);
temperature = (TextView) v.findViewById(R.id.temperature);
}
}
}
关于android - 将JSONArray放入列表(Android)，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/24376346/