java - 使用spring jdbc模板填充结果

我有两个类

class Deptartment{
  int deptid,
  String deptname;
  List<Employee> employees;

}

class Employee{

 int empid;
 String empname;
 int deptid;

}

Table:
Department:

    deptid,deptname

Employee

    empid,empname,deptid

Query: select * from deptartment d,employee e where  d.deptid= e.deptid

现在如何使用spring jdbc模板填充Department对象？

最佳答案

为了帮助肖恩·帕特里克·弗洛伊德(Sean Patrick Floyd)，下面是一个查询的解决方案:

final Map<Integer, Department> departments = new HashMap<Integer, Department>();
this.jdbcTemplate.query(
    "select d.deptid, d.deptname, e.empid, e.empname from Department d inner join Employee on e.deptid = e.deptid",
    new RowMapper<Employee>() {
        public Department mapRow(ResultSet rs, int rowNum) throws SQLException {
            Integer deptId = rs.getInt("deptid");
            Department d = (Department) departments.get(deptId);
            if (d == null) {
                String deptName = rs.getString("deptname");
                d = new Department();
                d.setDeptId(deptId);
                d.setDeptName(deptName);
                departments.put(deptId, d);
            }
            Employee employee = new Employee();
            employee.setEmpId(rs.getInt("empid"));
            employee.setEmpName(rs.getString("empname"));
            employee.setDeptId(deptId);
            d.getEmployees().add(employee);
            return employee;
        }
    });
List<Department> result = new ArrayList<Department>(departments.values());

它恰巧更短，更有效。

关于java - 使用spring jdbc模板填充结果，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/6521937/