我想用id=id，name，email，company自动填写div。。在点击任何搜索结果之后。搜索结果中的id用作从Mysql获取适当行的过滤器
数据来自search.php中使用的同一个表
这是我的表格
<link href="../action/css/onlinecustom.css" rel="stylesheet" type="text/css">
<script src="http://code.jquery.com/jquery-1.10.2.js" type="text/javascript"></script>
<script src="./action/scripts/global2.js" type="text/javascript"></script>
<script>
function searchq() {
var searchTxt = $("input[name='search']").val();
$.post("../action/subs/search.php/", {searchVal: searchTxt}, function(output) {
$("#output").html(output);
});
}
</script>
<title>Search</title>
<body>
<form action="http://comiut.com/index.php/user-records" method="post">
<input type="text" name="search" Placeholder="enter the search criteria..." onkeydown="searchq();"/>
<input type="submit" value ="serach"/>
</form>
//Serach result//
<div id="output"> </div>
//Data to populate upon click on any search result//
<div id="id"></div>
<div id="name"></div>
<div id="email"></div>
<div id="company_name"></div>
</body>
**我创建了一个global2.js文件**
jQuery('body').on('click', 'a.resultItem', function(e) {
e.preventDefault();
jQuery.ajax({
url: "http://onlinepcdoc.com/action/subs/getItem.php",
method: 'post',
data : jQuery(this).data('id') // see the data attribute we used above in the a tag we constructed
}).done(function(data) {
jQuery("#id").html(data.id);
jQuery("#name").html(data.name);
jQuery("#email").html(data.email);
jQuery("#company_name").html(data.company);
});
});
我还创建了search.php
<?php
include '../db/connect6.php';
if(isset($_POST['searchVal'])) {
$searchq = $_POST['searchVal'];
$searchq = preg_replace ("#[^0-9a-z]#i","",$searchq);
$query = mysql_query("SELECT * FROM oz2ts_users WHERE oz2ts_users.id LIKE '%$searchq%' OR oz2ts_users.name LIKE '%$searchq%'") or die("Could not search");
$count = mysql_num_rows($query);
if($count == 0){
$output = 'There is no result to show!';
} else{
while($row = mysql_fetch_array ($query)) {
$id = $row['id'];
$name = $row['name'];
$username = $row['username'];
$output .= '<div><a class="resultItem" data-id="' . $id . '">'
. $name . ' '.$username.'</a></div>';
}
}
}
echo($output);
?>
**这是getItem.php**
<?php
include '../db/connect6.php';
if(isset($_POST['id'])) {
$id = intval($_POST['id']);
$result = mysqli_query("SELECT oz2ts_users.id, oz2ts_users.name, oz2ts_users.username, oz2ts_users.email FROM oz2ts_users WHERE oz2ts_users.id = $id") or die("Could not search");
// since we expect only one result we don't need a loop
$row = mysqli_fetch_assoc($result);
// let's return the $row in json format
// first let's prepare the http header
header('Content-Type: application/json');
// and now we return the json payload
echo json_encode($row);
}
?>
最佳答案
你走的路是对的，虽然你自己什么都没试过，但这里有一些东西可以让你继续前进：
您应该返回类似的内容并填充搜索结果列表
$output .= '<div><a class="resultItem" data-id="' . $id . '">'
. $name . ' '.$username.'</a></div>';
接下来，您需要一个额外的ajax调用来填充底部信息，因此这里是javascript位，注意使用
clickbody构造将on事件绑定到动态创建的元素的方式：$('body').on('click', 'a.resultItem', function(e) {
e.preventDefault();
$.ajax({
url: "getItem.php",
method: 'post',
data : $(this).data('id') // see the data attribute we used above in the a tag we constructed
}).done(function(data) {
$("#id").html(data.id);
$("#name").html(data.name);
$("#email").html(data.email);
$("#company_name").html(data.company);
});
});
现在你只需要
getItem.php，它可以是这样的：<?php
include '../db/connect6.php';
if(isset($_POST['id'])) {
$id = intval($_POST['id']);
$result = mysqli_query("SELECT id,name,email,company FROM yourtable WHERE yourtable.id = $id") or die("Could not search");
// since we expect only one result we don't need a loop
$row = mysqli_fetch_assoc($result);
// let's return the $row in json format
// first let's prepare the http header
header('Content-Type: application/json');
// and now we return the json payload
echo json_encode($row);
}