我找到了这个perl脚本,但是我有太多的序列要分析我想知道是否可以优化它我在上面启动了NYTProf,看到“计算匹配分数”、“计算差距分数”和“选择最佳分数”部分花费了大量时间我需要修改数据结构吗?谢谢你的帮助。
带有引用的perl脚本:

    # Smith-Waterman  Algorithm
# from this website http://etutorials.org/Misc/blast/Part+II+Theory/Chapter+3.+Sequence+Alignment/3.2+Local+Alignment+Smith-Waterman/

# Smith-Waterman  Algorithm

# usage statement
die "usage: $0 <sequence 1> <sequence 2>\n" unless @ARGV == 2;

# get sequences from command line
my ($seq1, $seq2) = @ARGV;

# scoring scheme
my $MATCH    =  1; # +1 for letters that match
my $MISMATCH = -1; # -1 for letters that mismatch
my $GAP      = -1; # -1 for any gap

# initialization
my @matrix;
$matrix[0][0]{score}   = 0;
$matrix[0][0]{pointer} = "none";
for(my $j = 1; $j <= length($seq1); $j++) {
    $matrix[0][$j]{score}   = 0;
    $matrix[0][$j]{pointer} = "none";
}
for (my $i = 1; $i <= length($seq2); $i++) {
    $matrix[$i][0]{score}   = 0;
    $matrix[$i][0]{pointer} = "none";
}

# fill
my $max_i     = 0;
my $max_j     = 0;
my $max_score = 0;

for(my $i = 1; $i <= length($seq2); $i++) {
    for(my $j = 1; $j <= length($seq1); $j++) {
        my ($diagonal_score, $left_score, $up_score);

        # calculate match score
        my $letter1 = substr($seq1, $j-1, 1);
        my $letter2 = substr($seq2, $i-1, 1);
        if ($letter1 eq $letter2) {
            $diagonal_score = $matrix[$i-1][$j-1]{score} + $MATCH;
        }
        else {
            $diagonal_score = $matrix[$i-1][$j-1]{score} + $MISMATCH;
        }

        # calculate gap scores
        $up_score   = $matrix[$i-1][$j]{score} + $GAP;
        $left_score = $matrix[$i][$j-1]{score} + $GAP;

        if ($diagonal_score <= 0 and $up_score <= 0 and $left_score <= 0) {
            $matrix[$i][$j]{score}   = 0;
            $matrix[$i][$j]{pointer} = "none";
            next; # terminate this iteration of the loop
        }

        # choose best score
        if ($diagonal_score >= $up_score) {
            if ($diagonal_score >= $left_score) {
                $matrix[$i][$j]{score}   = $diagonal_score;
                $matrix[$i][$j]{pointer} = "diagonal";
            }
            else {
                $matrix[$i][$j]{score}   = $left_score;
                $matrix[$i][$j]{pointer} = "left";
            }
        } else {
            if ($up_score >= $left_score) {
                $matrix[$i][$j]{score}   = $up_score;
                $matrix[$i][$j]{pointer} = "up";
            }
            else {
                $matrix[$i][$j]{score}   = $left_score;
                $matrix[$i][$j]{pointer} = "left";
            }
        }

        # set maximum score
        if ($matrix[$i][$j]{score} > $max_score) {
            $max_i     = $i;
            $max_j     = $j;
            $max_score = $matrix[$i][$j]{score};
        }
    }
}

# trace-back

my $align1 = "";
my $align2 = "";

my $j = $max_j;
my $i = $max_i;

while (1) {
    last if $matrix[$i][$j]{pointer} eq "none";

    if ($matrix[$i][$j]{pointer} eq "diagonal") {
        $align1 .= substr($seq1, $j-1, 1);
        $align2 .= substr($seq2, $i-1, 1);
        $i--; $j--;
    }
    elsif ($matrix[$i][$j]{pointer} eq "left") {
        $align1 .= substr($seq1, $j-1, 1);
        $align2 .= "-";
        $j--;
    }
    elsif ($matrix[$i][$j]{pointer} eq "up") {
        $align1 .= "-";
        $align2 .= substr($seq2, $i-1, 1);
        $i--;
    }
}

$align1 = reverse $align1;
$align2 = reverse $align2;
print "$align1\n";
print "$align2\n";

最佳答案

你可以试着避免重复做同样的事情。
不要从序列中删除单个字符,您可以尝试在循环之前将序列分成一次字符,而不是使用最可能更快的通过索引的访问。
例子:

my $string = "Hello, how are you?";
my @chars = split //, $string;  # Or: unpack 'a*', $string
print "Eighth char: $chars[7]\n";

my $letter2 = substr($seq2, $i-1, 1);可以转到外部循环,因为j在内部循环中从不更改。
for(my $i = 1; $i <= length($seq2); $i++) {
    my $letter2 = substr($seq2, $i-1, 1);
    for(my $j = 1; $j <= length($seq1); $j++) {

避免缓慢而复杂的C风格循环。
for my $i (1..length($seq2)) {
    my $letter2 = substr($seq2, $i-1, 1);
    for my $j (1..length($seq1)) {

用整数代替字符串表示pointer的值。您可以使用常量来保持其可读性。
use constant {
   POINTER_NONE => 0,
   POINTER_LEFT => 1,
   ...
};

预先计算$j-1$i-1也可能带来一个小的优势。
请注意,您应该在每次更改之前和之后分析代码,以查看速度是否增加。
所有这些都是小的改进真正的问题是你有一个二次算法。

关于algorithm - 如何修改Smith和Waterman perl脚本以加快运行速度?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/47754639/

10-13 00:50