python - 如何通过BucketType定义命令错误消息

我对一个命令使用max_concurrency两次，以限制每个公会最多调用3次，每个用户最大一次调用:

@commands.max_concurrency(3,per=commands.BucketType.guild,wait=False)
@commands.max_concurrency(1,per=commands.BucketType.user,wait=False)
async def start(self, ctx):

我的问题是如何使用BucketType参数创建单独的错误消息。
例如，我要问的是:

@start.error
async def on_command_error(self,ctx,error):

        if isinstance(error, commands.MaxConcurrencyReached):

              guild_error = "Too many playing"
              user_error = "You're already playing"

              await ctx.send("guild_error or user_error depending on BucketType?")

最佳答案

通过使用MaxConcurrencyReached.per属性，我们可以找到BucketType并采取相应的措施。
例如:

@start.error
async def on_command_error(self,ctx,error):

        if isinstance(error, commands.MaxConcurrencyReached):

              guild_error = "Too many playing"
              user_error = "You're already playing"
              # Because error.per returns a BucketType, we can check it against BucketType.user and BucketType.guild.
              if error.per == commands.BucketType.user:
                  await ctx.send(user_error)
              elif error.per == commands.BucketType.guild:
                  await ctx.send(guild_error)