c - 将内存分配给结构内部的指针结构

如果我有这样的结构

typedef struct _people {
 char *name;

 bool *exists;

 struct _people **citizens;
} PEOPLE;

我该如何分配内存以便人们->公民[0]>姓名可以访问？我试过了

info->citizens = malloc(sizeof(PEOPLE *)*numbPeople);

但是，当我尝试访问info->citizens->name时，我会在GDB中收到错误消息：

Program received signal EXC_BAD_ACCESS, Could not access memory.
Reason: KERN_INVALID_ADDRESS at address: 0x0000000000000008

最佳答案

（我无缘无故不喜欢C中的类型定义结构）
让sizeof为你做这项工作。

info->citizens = malloc(numbPeople * sizeof *info->citizens)
if (!info->citizens) { /* could not malloc - do something */ }

int i;
for (i = 0; i < numbPeople; ++i) {
    info->citizens[i] = malloc(sizeof *info->citizens[i]);
    if (!info->citizens[i]) { /* could not malloc - do something */ }
}