我想问一下我的程序有什么问题..
我的程序是关于堆栈的,没有错误,但是我的问题是,我们的要求是在堆栈中进行所有操作,然后,即使您关闭程序,下次打开它时,仍应显示先前的数据..
我使用了文件写入器和文件读取器,但是每次关闭它,然后再次打开它时,都不会显示以前的数据。
有什么建议吗?
谢谢..这是我的程序..

import java.util.*;
import java.awt.*;
import java.io.*;
import javax.swing.*;
import java.awt.event.*;
public class STACKS extends JFrame implements ActionListener
{
    private JButton push,pop,peek,display,exit;
    private JLabel Stack;
    static int arr[],x=0,b=0,xy=0,c=0;
    static String in="",INDEX="",d="",s="";
    static String id[]={};

    public STACKS()
    {
        super("STACKS MENU!^_^");
        Container c=getContentPane();
        c.setLayout(new FlowLayout());
        Stack=new JLabel("STACKS MENU!^_^");    c.add(Stack);
        push=new JButton("Push!^-^");
        pop=new JButton("Pop!^-^");
        peek=new JButton("Peek!^-^");
        display=new JButton("Display!^-^");
        exit=new JButton("Exit!^-^");
        push.addActionListener(this);           c.add(push);
        pop.addActionListener(this);            c.add(pop);
        peek.addActionListener(this);           c.add(peek);
        display.addActionListener(this);        c.add(display);
        exit.addActionListener(this);           c.add(exit);
        setVisible(true);
        setSize(150,250);
    }
    public static void saveMe() throws IOException
    {
        File data1=new File("Sample.txt");      //a file was created...
        PrintWriter out=new PrintWriter(new BufferedWriter(new FileWriter(data1,true)));
        for(int x=0;x<4;x++)
        {
            out.write(":"+arr[x]);  xy=1;           //here in this section, I put : in every elements inside the array..
        }
        out.close();

    }
    public static void readMe() throws IOException
    {
        Scanner txtFile=(new Scanner("Sample.txt"));

        for(int y=0;x<id.length;y++)
        {
            s=txtFile.nextLine();
            id=s.split(":");
            arr[y]=Integer.parseInt(id[y]);
        }

    }
    public  void actionPerformed(ActionEvent a)
    {
        try
        {
            readMe();                               //here is where the previous data will be read..
        }
        catch(Exception e)
        {
            JOptionPane.showMessageDialog(null,"File not found! readme !^,^");
        }
        if (xy==0)
        {
            INDEX=JOptionPane.showInputDialog(null,"Enter LENGTH of the array!");
            c=Integer.parseInt(INDEX); xy=1;
            arr=new int[c];
        }
        if(a.getSource()==push)
        {
            in=JOptionPane.showInputDialog(null,"Enter integer to be pushed!");
            b=Integer.parseInt(in);
            arr[x]=b;   x+=1;
            if(x==c)
            {
                JOptionPane.showMessageDialog(null,"WARNING! The stacks are full, please pop something!^-^");
            }
            if(x>c)
            {
                JOptionPane.showMessageDialog(null,"Sorry, the stacks are full,please pop something first!^-^");
                x-=1;
            }
        }
        else if(a.getSource()==pop)
        {

            arr[x-1]=0;x-=1;
            JOptionPane.showMessageDialog(null,"The value has been popped!^-^");
            if(x==0)
            {
                JOptionPane.showMessageDialog(null,"The stacks are empty, push something!^-^");
            }

        }
        else if(a.getSource()==peek)
        {
            JOptionPane.showMessageDialog(null,"The value is "+arr[x-1]+"! ^-^");
        }
        else if(a.getSource()==display)
        {
            for(int y=c-1;y>-1;y--)
            {
                d+="*** "+arr[y]+" ***\n";
            }
            JOptionPane.showMessageDialog(null,"The value inside the stacks are:\n"+d);
            d="";
        }
        else if(a.getSource()==exit)
        {
            System.exit(0);
        }
            try
        {
            saveMe();                   //here is where the file will be saved..
        }
        catch(Exception e)
        {
            JOptionPane.showMessageDialog(null,"File not found!^,^");
        }
    }
    public static void main(String args[])
    {
        STACKS pot=new STACKS();
        pot.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

    }
}

最佳答案

实际上,这里有很多问题。

根据Alexander的回答,您确实在每次Push / pop调用之后都进行了保存,因此将调用saveMe()

但是,在saveMe()中,您将:写入堆栈的第一个元素之前,因此将其读回将始终提供一个额外的空白元素。写入:之前,请检查x!= 0。

readMe()中,您要为id.length调用nextLine(),这在两种方法中是不正确的:


当您启动程序时,id的长度为零。您不应将x<id.length用作for循环的结束条件(无论如何x都是错误的,在您的上下文中应该为y)。使用txtFile.hasNext()检查是否还有其他堆栈元素要读取。
您的文件完全在一行中包含堆栈,而不是多行。您应该做的是使用:将扫描仪的分隔符设置为textFile.useDelimiter(":"),然后调用next()。还请记住,除非更正saveMe(),否则开头将有一个多余的元素为空白。


同样在readMe()中,根据Nicklamort的回答,您需要调用new Scanner(new File("Sample.txt"))打开实际文件。

新的readMe()示例

public static void readMe() throws IOException
{
    Scanner txtFile=(new Scanner(new File("Sample.txt")));
    int y = 0;
    txtFile.useDelimiter(":");
    while(txtFile.hasNext())
    {
        arr[y]=txtFile.nextInt();
        y++;
    }

}


新的saveMe()示例

public static void saveMe() throws IOException
{
    File data1=new File("Sample.txt");      //a file was created...
    PrintWriter out=new PrintWriter(new BufferedWriter(new FileWriter(data1,false))); // don't append, overwrite existing data since we are saving the entire stack each time
    for(int x=0;x<arr.length;x++)
    {
        if(x != 0) { out.write(":"); }           //here in this section, I put : in every elements inside the array..
        out.write(arr[x]);  xy=1;
    }
    out.flush(); // force writing to disk
    out.close();
}

10-08 08:17