给定一个由包含一系列口语单词的AKAudioFile
创建的单个AKNodeRecorder
,其中每个单词之间至少间隔1秒钟,最好的方法是最终创建一系列文件(每个文件包含一个单词)?
我相信,如果有一种方法可以迭代文件(例如100 ms的块)并测量每个块的平均幅度,则可以实现此目的。 “静音块”可能是低于任意小幅度的那些。进行迭代时,如果遇到一个具有非静默振幅的块,则可以获取此“非静默”块的开始时间戳,以创建一个从此处开始并在下一个“静默”块的开始时间结束的音频文件。
无论是使用上述手动方法还是AudioKit的内置处理技术,任何建议都将不胜感激。
最佳答案
我没有完整的解决方案,但是我已经开始从事与此类似的工作。此功能可以作为您所需的起点。基本上,您希望将文件读入缓冲区,然后分析缓冲区数据。那时,您可以将其切成较小的缓冲区,然后将其写入文件。
public class func guessBoundaries(url: URL, sensitivity: Double = 1) -> [Double]? {
var out: [Double] = []
guard let audioFile = try? AVAudioFile(forReading: url) else { return nil }
let processingFormat = audioFile.processingFormat
let frameCount = AVAudioFrameCount(audioFile.length)
guard let pcmBuffer = AVAudioPCMBuffer(pcmFormat: processingFormat, frameCapacity: frameCount) else { return nil }
audioFile.framePosition = 0
do {
audioFile.framePosition = 0
try audioFile.read(into: pcmBuffer, frameCount: frameCount)
} catch let err as NSError {
AKLog("ERROR: Couldn't read data into buffer. \(err)")
return nil
}
let channelCount = Int(pcmBuffer.format.channelCount)
let bufferLength = 1024
let inThreshold: Double = 0.001 / sensitivity
let outThreshold: Double = 0.0001 * sensitivity
let minSegmentDuration: Double = 1
var counter = 0
var thresholdCrossed = false
var rmsBuffer = [Float](repeating: 0, count: bufferLength)
var lastTime: Double = 0
AKLog("inThreshold", inThreshold, "outThreshold", outThreshold)
for i in 0 ..< Int(pcmBuffer.frameLength) {
// n is the channel
for n in 0 ..< channelCount {
guard let sample: Float = pcmBuffer.floatChannelData?[n][i] else { continue }
if counter == rmsBuffer.count {
let time: Double = Double(i) / processingFormat.sampleRate
let avg = rmsBuffer.reduce(0, +) / rmsBuffer.count
// AKLog("Average Value at frame \(i):", avg)
if avg > inThreshold && !thresholdCrossed && time - lastTime > minSegmentDuration {
thresholdCrossed = true
out.append(time)
lastTime = time
} else if avg <= outThreshold && thresholdCrossed && time - lastTime > minSegmentDuration {
thresholdCrossed = false
out.append(time)
lastTime = time
}
counter = 0
}
rmsBuffer[counter] = abs(sample)
counter += 1
}
}
rmsBuffer.removeAll()
return out
}
关于ios - 将AKAudioFile拆分成由静音分隔的块,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/51432115/