我正在尝试创建一个将函数指针作为参数的函数指针，但是不确定如何去做...建议我尝试对我的函数指针之一进行类型定义，但会遇到相同的错误。有人可以为我提供正确的语法吗？
int
186 main(int argc, char **argv)
187 {
188 int i;
194 typedef int (*search_alg) (int *, int, int);
195 typedef int (*search) (search_alg);
196 set_t (*intersect_alg) (list_t *, (search));
197
198 clo_t *iopts = parse_args(argc, argv);
199
200 /* select interstion algorithm */
201 switch (iopts->imode) {
202 case SVS:
203 fprintf(stdout, "ALGORITHM : SvS\n");
204 intersect_alg = svs;
205 break;
206 case SEQ:
207 fprintf(stdout, "ALGORITHM : Sequential\n");
208 intersect_alg = sequential;
209 break;
210 case ADP:
211 fprintf(stdout, "ALGORITHM : Adaptive\n");
212 intersect_alg = adaptive;
213 break;
214 default:
215 fprintf(stdout, "ALGORITHM : Unknown\n");
216 return (EXIT_FAILURE);
217 }
218
219 /* select fsearch algorithm */
220 switch (iopts->mode) {
221 case LIN:
222 fprintf(stdout, "F-SEARCH : Linear\n");
223 search = linear_fsearch;
224 break;
225 case BIN:
226 fprintf(stdout, "F-SEARCH : Binary\n");
227 search = binary_fsearch;
228 break;
229 case INP:
230 fprintf(stdout, "F-SEARCH : Interpolation\n");
231 search = interpolation_fsearch;
232 break;
233 case EXP:
234 fprintf(stdout, "F-SEARCH : Exponential\n");
235 search = exponential_fsearch;
236 break;
237 default:
238 fprintf(stdout, "F-SEARCH : Unknown\n");
239 return (EXIT_FAILURE);
240 }
241
244
245 /* perform intersection and run timings */
246 for (i = 0; i < iopts->runs; i++) {
248 /* perform intersect search */
249 intersect_alg (iopts->data_files, search);
252 }
我要打的那条线是249，我最初尝试过
int (*search_alg) (int *, int, int);
set_t (*intersect_alg) (list_t *, (*) (int *, int, int);
如果可能的话，可能会更喜欢这样做。我得到的错误是:
main.c:204: warning: assignment from incompatible pointer type
main.c:208: warning: assignment from incompatible pointer type
main.c:212: warning: assignment from incompatible pointer type
我要指向的功能是:
22 /** Finger Search Operations for array sets **/
23 int linear_fsearch(int *set, int len, int key);
24 int binary_fsearch(int *set, int len, int key);
25 int interpolation_fsearch(int *set, int len, int key);
26 int exponential_fsearch(int *set, int len, int key);
27
28 /** Intersect Algorithms **/
29 set_t *svs(list_t * list, int (*srch_alg) (int *, int, int));
30 set_t *sequential(list_t * list, int (*srch_alg) (int *, int, int ));
31 set_t *adaptive(list_t * list, int (*srch_alg) (int *, int, int));
有人可以看到我在做什么错吗？我不知道。
谢谢!
Rhys。
最佳答案
您需要的intersect_alg声明是
set_t *(*intersect_alg)(list_t *, int (*)(int *, int, int));
关于c - 创建一个将函数指针作为参数的函数指针，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/2865693/