我正在尝试在Tomcat 7上运行Apache Jersey REST的Windows Server 2008 R2上通过cURL命令行执行以下命令。
curl -X POST -d "<userList xmlns="urn:user"><user role="ROLE_OPERATOR" loginName="test_login1"></user></userList>" -H "Content-Type: application/xml" --basic --user username:password http://localhost:8080/meolutws/UserList/
当我发出命令时,我得到带有消息的HTTP 400:“客户端发送的请求在语法上是不正确的”。
Web服务上的方法签名看起来像这样:
@POST
@CONSUMES({"application/xml"})
public Response createUsers(UserList users){
}
UserList类的定义如下:
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "UserList", namespace = "urn:user", propOrder = {
"users"
})
@XmlRootElement(name = "userList", namespace = "urn:user")
public class UserList
implements Serializable
{
@XmlElement(name = "user")
protected List<User> users;
public List<User> getUsers() {
if (users == null) {
users = new ArrayList<User>();
}
return this.users;
}
}
用户定义如下:
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "User", namespace = "urn:user")
@XmlRootElement(name = "user", namespace = "urn:user")
public class User
implements Serializable
{
@XmlAttribute(name = "loginName", required = true)
protected String loginName;
@XmlAttribute(name = "role", required = true)
protected String role;
public String getLoginName() {
return loginName;
}
public void setLoginName(String value) {
this.loginName = value;
}
public String getRole() {
return role;
}
public void setRole(String value) {
this.role = value;
}
}
我想念什么?
最佳答案
引号的用法看起来是错误的。你做这个:
curl -X POST \
-d "<userList xmlns="urn:user"><user role="ROLE_OPERATOR" loginName="test_login1"></user></userList>" \
-H "Content-Type: application/xml" \
--basic --user meo:meo \
http://localhost:8080/meolutws/UserList/
你的身体是:
"<userList xmlns="urn:user"><user role="ROLE_OPERATOR" loginName="test_login1"></user></userList>"
您不能使用引号
"
进行转义。如果使用'
,会发生错误吗?'<userList xmlns="urn:user"><user role="ROLE_OPERATOR" loginName="test_login1"></user></userList>'