perl - 如何在POE堆上放置数组并推送或弹出数据？

我如何在POE堆上放置一个数组，并向其中推入/弹出数据？

我试图将以下数组放在堆上:

@commands = (
    ["quit",\&Harlie::Commands::do_quit,10],
    ["part",\&Harlie::Commands::do_part,10],
    ["join",\&Harlie::Commands::do_join,10],
    ["nick",\&Harlie::Commands::do_nick,10],
    ["module",\&Harlie::Commands::do_modules,10],
    ["uptime",\&Harlie::Commands::do_uptime,0]
);

我将如何访问其中包含的函数引用？目前，我可以通过以下方式运行它们:

@commands->[$foo]->(@bar);

我会以为它会是正确的吗？:

$heap->{commands}->[$foo]->(@bar);

最佳答案

要在POE堆上创建/使用数组，仅是将引用包装在“@ {...}”中的情况。
例如。:

use strict;
use warnings;
use POE;
use POE::Kernel;

POE::Session->create(
    inline_states =>{
        _start =>   \&foo,
        bar    => \&bar}
);

sub foo{
    my ($kernel, $heap) = @_[KERNEL, HEAP];
    @{$heap->{fred}} = ("foo","bar","baz");
    $kernel->yield("bar");
}

sub bar{
    my ($kernel, $heap) = @_[KERNEL, HEAP];
    print "Length of array fred... " . ($#{$heap->{fred}}+1) . "\n";
    print "Contents of fred... ";
    foreach(@{$heap->{fred}}){
    print $_ . " ";  }
    print "\n";
}

POE::Kernel->run();

但是，数组的数组不是，而是。从上面逻辑上遵循的程序...

use strict;
use warnings;
use POE;
use POE::Kernel;

POE::Session->create(
    inline_states    => {
    _start =>    \&foo,
    bar    =>    \&bar
    }
    );

sub foo{
    my ($kernel, $heap) = @_[KERNEL, HEAP];

    @{$heap->{fred}} = (
        ["foo","bar","baz"],
        ["bob","george","dan"]
    );
    $kernel->yield("bar");
}

sub bar{
    my ($kernel, $heap) = @_[KERNEL, HEAP];
    print "Length of array fred... " . ($#{$heap->{fred}}+1) . "\n";
    print @{$heap->{fred}}[0][0];

}

POE::Kernel->run();

...仅给出以下错误。

perl ../poe-test.pl
../poe-test.pl第26行，“] [”附近的语法错误
../poe-test.pl的执行由于编译错误而中止。