考虑下表:
部门
deptid (type:INT)
deptname (type: TEXT)
hours (type:INT)
active (type:BIT)
雇员
empid (type:INT)
empname (type: TEXT)
deptid (type: INT)
designation (type: TEXT)
salary (type: INT)
编写一个查询以返回empname和deptname列
总人数达到或超过4人的部门。记录应按empname的字母顺序返回
这是我拍的:
SELECT e1.empname, d.deptname from employee AS e1
FULL JOIN department AS d on e1.deptid = d.deptid
WHERE e1.deptid IN(
SELECT deptid FROM(
SELECT e2.deptid, COUNT(e2.empid)
FROM employee AS e2
GROUP BY e2.deptid
HAVING COUNT(e2.empid) >= 4
)
)
ORDER BY empname;
你将如何改进?
最佳答案
这是较短的,可能表现得也更快
SELECT e1.empname, d.deptname
from (
SELECT e2.deptid
FROM employee AS e2
GROUP BY e2.deptid
HAVING COUNT(e2.empid) >= 4
) G
inner join employee AS e1 on e1.deptid = G.deptid
INNER JOIN department AS d on d.deptid = G.deptid
ORDER BY e1.empname;
从分组开始。您不需要从内部查询中进行计数。
然后,连接到两个表以获取名称。
使用内部连接是因为一旦计数完成,我们已经知道
员工存在
部门存在