如何将函数inet_ntop(const char *)的返回值转换为string

编码:

string ip = inet_ntop(b->ifa_addr->sa_family,tempAddrPtr,addressOutputBuffer, sizeof(addressOutputBuffer));

总是导致segfault ...
struct ifaddrs *a;
void *tempAddrPtr = NULL;
struct ifaddrs *b;
char addressOutputBuffer[INET6_ADDRSTRLEN];
int i=0;
i=getifaddrs(&a);
cout << i;
b=a;
cout << name;
for (b = a; b; b = b->ifa_next) {
        cout << b->ifa_name;

        if(b->ifa_addr->sa_family == AF_INET)
            tempAddrPtr = &((struct sockaddr_in *)b->ifa_addr)->sin_addr;
          else
            tempAddrPtr = &((struct sockaddr_in6 *)b->ifa_addr)->sin6_addr;
        printf(" Internet Address:  %s \n",
                     inet_ntop(b->ifa_addr->sa_family,
                               tempAddrPtr,
                               addressOutputBuffer,
                               sizeof(addressOutputBuffer)));
                     string ip = inet_ntop(b->ifa_addr->sa_family,tempAddrPtr,addressOutputBuffer, sizeof(addressOutputBuffer));

}
freeifaddrs(a);

最佳答案

inet_ntop返回char *,如果您的inet_ntop返回,则将正确生成字符串ip对象。突变部分是inet_ntop参数,即带有指针的参数。

一些调试提示:

1. check b is null or not
2. tempAddrPtr is valid or not
3. addressOutputBuffer is valid or not

08-26 01:42