旋转屏幕时,ArrayAdapter中的数据将消失。有人知道如何解决吗?
我在MainActivity.cs中的代码
private int count = 0;
private IList<string> intervals = new List<string>();
private ArrayAdapter<string> listAdapter;
protected override void OnCreate(Bundle bundle)
{
base.OnCreate(bundle);
SetContentView(Resource.Layout.Main);
this.timeView = FindViewById<TextView>(Resource.Id.timeView);
this.interval = FindViewById<ListView>(Resource.Id.interval);
this.listAdapter = new ArrayAdapter<string>(this,Android.Resource.Layout.SimpleListItem1, intervals);
this.interval.Adapter = listAdapter;
RunOnUiThread(() => { listAdapter.NotifyDataSetChanged();});
this.timeView.Click += (IntentSender, eventArgs) => addInterval();
}
private void addInterval() {
this.listAdapter.Insert(++this.count + "\t\t\t\t" + string.Format("{0:hh\\:mm\\:ss\\.fff}",this.accumulatedTime),0);
}
提前致谢!!
最佳答案
旋转屏幕时,当前活动被拆除。没有id
的任何项目都将失去其价值。
因此尝试使用
public void onSaveInstanceState(Bundle savedState) {
super.onSaveInstanceState(savedState);
String[] aavalues = aAdapter.getValue();
savedState.putStringArray("enter a key value here", aavalues);}
您必须定义一个
getValue
方法来获取适配器内部的值。然后,由于您的活动被销毁,它将再次输入
oncreate
。在此处初始化适配器
String[] avalues = savedInstanceState.getStringArray("the key value from before");
if (values != null) {
aAdaptor = new MyAdaptor(avalues);}