根据Ruby Set类的文档,“==如果两个集合相等,则返回true。每对元素的相等性是根据Object#eql?定义的。
可以使用Date对象来演示其本质,其中包含不同Date对象但具有相同日期的集合比较等于:
require 'set'
d1 = Date.today # => Thu, 30 Sep 2010
puts d1.object_id # => 2211539680
d2 = Date.today + 1 # => Fri, 01 Oct 2010
puts d2.object_id # => 2211522320
set1 = Set.new([d1, d2])
d11 = Date.today # => Thu, 30 Sep 2010
puts d11.object_id # => 2211489080
d12 = Date.today + 1 # => Fri, 01 Oct 2010
puts d12.object_id # => 2211469380
set2 = Set.new([d12, d11])
set1 == set2 # => true
但是使用我自己的对象,我在哪里编码了eql?仅比较某些属性的方法,我无法使其正常工作。
class IpDet
attr_reader :ip, :gateway
def initialize(ip, gateway, netmask, reverse)
@ip = ip
@gateway = gateway
@netmask = netmask
@reverse = reverse
end
def eql?(other)
if @ip = other.ip && @gateway == other.gateway
return true
else
return false
end
end
end
ipdet1 = IpDet.new(123456, 123457, 123458, 'example.com')
ipdet2 = IpDet.new(234567, 2345699, 123458, 'nil')
ipdet11 = IpDet.new(123456, 123457, 777777, 'other_domain.com')
ipdet12 = IpDet.new(234567, 2345699, 777777, 'example.com')
puts "ipdet1 is equal to ipdet11: #{ipdet1.eql?(ipdet11)}"
puts "ipdet2 is equal to ipdet12: #{ipdet2.eql?(ipdet12)}"
set1 = Set.new([ipdet1, ipdet2])
set2 = Set.new([ipdet11, ipdet12])
puts "set 1 is equal to set2: #{set1 == set2}"
我从上面得到的输出是:
ipdet1 is equal to ipdet11: true
ipdet2 is equal to ipdet12: true
set 1 is equal to set2: false
有任何想法吗?
最佳答案
当覆盖eql?
时,还始终需要覆盖hash
,以便如果o1.eql?(o2)
为true,则o1.hash == o2.hash
也为true。
例如,您的哈希方法可能如下所示:
def hash
[@ip, @gateway].hash
end
另外,您的
eql?
方法中有一个错字:@ip = other.ip
应该是@ip == other.ip
。也是次要的样式说明:
if condition then true else false end
等效于condition
,因此您的eql?
方法可以定义为def eql?(other)
@ip == other.ip && @gateway == other.gateway
end
关于ruby - Ruby Set类: equality of sets,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/3832703/