python - 在python中提取不匹配的字符串

我有两个字符串s和s2

s = "catwalksonterrace9_ontheweekend_at7am"
s2= "catwalksonterrace$no_ontheweekend_at.*"

我需要比较两个字符串并提取不匹配的部分
Python中两个字符串中的$no = 9和.* = 7am。我是python的新手，我将如何实现呢？

最佳答案

看一下difflib，它很棒，可以完全按照您想要的去做:)
https://docs.python.org/2/library/difflib.html

import difflib
d = difflib.Differ()
diffs = []
in_diff = False
for c in d.compare(s, s2):
    if not in_diff and (c.startswith("+") or c.startswith("-")):
        diffs.append(["", ""])
        in_diff = True
    if c.startswith("+"):
        diffs[-1][0] += c.replace("+ ", "")
    elif c.startswith("-"):
        diffs[-1][1] += c.replace("- ", "")
    else:
        in_diff = False
print(diffs)

这将创建一个列表列表，其中每个子列表的第一个值在第1行为diff，第二个值在第2行为diff

输出将是：

[['$no', '9'], ['.*', '7am']]

然后，您可以循环浏览，按要求打印：

for diff in diffs:
    print(diff[0], "=", diff[1])