我正在用JavaScript开发一个Snake游戏,我希望Snake只能垂直或水平移动,但它会一直沿对角线移动。例如,如果我向上按,它会向上移动,但如果我向右按,它将沿对角线移动,而不是仅向右移动。
const canvas = document.querySelector('canvas')
const ctx = canvas.getContext('2d')
const length_width = 15;
let snakeCoord = [
{x:300,y:150},
{x:315,y:150},
{x:330,y:150},
{x:345,y:150},
{x:360,y:150},
{x:375,y:150}
];
function drawSnakePart(snakePart) {
ctx.beginPath();
ctx.fillRect(snakePart.x, snakePart.y, length_width, length_width);
ctx.strokeRect(snakePart.x, snakePart.y, length_width, length_width);
ctx.closePath();
}
function drawSnake() {
snakeCoord.forEach(drawSnakePart);
}
function moveSnake(dx, dy) {
const head = {
x: snakeCoord[0].x + dx,
y: snakeCoord[0].y + dy
};
snakeCoord.unshift(head);
snakeCoord.pop();
ctx.clearRect(0, 0, canvas.width, canvas.height);
drawSnake();
setTimeout(function() {
moveSnake(dx, dy)
}, 100);
}
function keyPress(e) {
let key = e.key;
if (key == "ArrowUp") {
if (snakeCoord[0].y - length_width !== snakeCoord[1].y) {
moveSnake(0, -length_width);
}
} else if (key == "ArrowDown") {
if (snakeCoord[0].y + length_width !== snakeCoord[1].y) {
moveSnake(0, length_width);
}
} else if (key == "ArrowLeft") {
if (snakeCoord[0].x - length_width !== snakeCoord[1].x) {
moveSnake(-length_width, 0);
}
} else if (key == "ArrowRight") {
if (snakeCoord[0].x + length_width !== snakeCoord[1].x) {
moveSnake(length_width, 0);
}
}
}
drawSnake();
document.addEventListener("keyup", keyPress);
<canvas width="500" height="500"></canvas>
最佳答案
在每次按键时,然后递归地设置新的超时setTimeout(function(){ moveSnake(dx,dy) }, 100);
。你最终会接到越来越多的有争议的电话。
您应该将超时保存到一个变量,并在调用moveSnake
之前用键盘上的clearTimeout()
清除它。