使用Espresso是否可以简化这两个语句?
onView(withText(expectedErrorTitle))
.check(matches(isDisplayed()));
onView(withText(expectedErrorMessage))
.check(matches(isDisplayed()));
我尝试了这个,但是不起作用:
onView(allOf(
withText(expectedErrorTitle),
withText(expectedErrorMessage)
)).check(matches(isDisplayed()));
最佳答案
为什么还要简化?但是您可以检查父视图,以使子级具有预期的文本。
onView(R.id.parentLayout)
.check(matches(allOf(
isDisplayed(),
withChild(withText("A")),
withChild(withText("B"))
)));
检查是否显示了父级就足够了,或者您做了更多疯狂的事情,例如
onView(R.id.parentLayout)
.check(matches(allOf(
withChild(allOf(withText("A"), isDisplayed())),
withChild(allOf(withText("B"), isDisplayed())),
)));