第十一章 条件逻辑

1. 基本描述

　　本藏主要讲解SQL语句中的条件逻辑。

2. 基本样例

SELECT c.cust_id, c.fed_id, c.cust_type_cd, CONCAT(i.fname, ' ', i.lname) indiv_name,
b.name business_name FROM customer c LEFT OUTER JOIN individual i ON c.cust_id = i.cust_id
LEFT OUTER JOIN business b ON c.cust_id = b.cust_id;

SELECT c.cust_id, c.fed_id,
CASE
    WHEN c.cust_type_cd = 'I'
        THEN CONCAT(i.fname, ' ', i.lname)
    WHEN c.cust_type_cd = 'B'
        THEN b.name
    ELSE 'Unknown'
END name
FROM customer c LEFT OUTER JOIN individual i
ON c.cust_id = i.cust_id
LEFT OUTER JOIN business b
ON c.cust_id = b.cust_id;

SELECT c.cust_id, c.fed_id,
CASE
    WHEN c.cust_type_cd = 'I' THEN
        (SELECT CONCAT(i.fname, ' ', i.lname) FROM individual i  WHERE i.cust_id = c.cust_id)
    WHEN c.cust_type_cd = 'B' THEN
        (SELECT b.name FROM business b WHERE b.cust_id = c.cust_id)
    ELSE 'Unknown'
END name
FROM customer c;

SELECT YEAR(open_date) year, COUNT(*) how_many
FROM account WHERE open_date > '1999-12-31' AND open_date < '2006-01-01'
GROUP BY YEAR(open_date);

SELECT
SUM(CASE
        WHEN EXTRACT(YEAR FROM open_date) = 2000 THEN 1 ELSE 0 END) year_2000,
SUM(CASE
        WHEN EXTRACT(YEAR FROM open_date) = 2001 THEN 1 ELSE 0 END) year_2001,
SUM(CASE
        WHEN EXTRACT(YEAR FROM open_date) = 2002 THEN 1 ELSE 0 END) year_2002,
SUM(CASE
        WHEN EXTRACT(YEAR FROM open_date) = 2003 THEN 1 ELSE 0 END) year_2003,
SUM(CASE
        WHEN EXTRACT(YEAR FROM open_date) = 2004 THEN 1 ELSE 0 END) year_2004,
SUM(CASE
        WHEN EXTRACT(YEAR FROM open_date) = 2005 THEN 1 ELSE 0 END) year_2005
FROM account
WHERE open_date > '1999-12-31' AND open_date < '2006-01-01';

SELECT c.cust_id, c.fed_id, c.cust_type_cd,
CASE
    WHEN EXISTS(SELECT 1 FROM account a WHERE a.cust_id = c.cust_id AND a.product_cd = 'CHK') THEN 'Y'
    ELSE 'N'
END has_checking,
CASE
    WHEN EXISTS(SELECT 1 FROM account a WHERE a.cust_id = c.cust_id AND a.product_cd = 'SAV') THEN 'Y'
    ELSE 'N'
END has_savings
FROM customer c;

SELECT c.cust_id, c.fed_id, c.cust_type_cd,
CASE (SELECT COUNT(*) FROM account a WHERE a.cust_id = c.cust_id)
    WHEN 0 THEN 'None'
    WHEN 1 THEN '1'
    WHEN 2 THEN '2'
    ELSE '3+'
END num_accounts
FROM customer c;

SELECT a.cust_id, a.product_cd, a.avail_balance /
CASE
    WHEN prod_tots.tot_balance = 0 THEN 1
    ELSE prod_tots.tot_balance
END percent_of_total
FROM account a INNER JOIN
    (SELECT a.product_cd, SUM(a.avail_balance) tot_balance FROM account a GROUP BY a.product_cd) prod_tots
ON a.product_cd = prod_tots.product_cd;