php - 试图计数并返回表中的行数

我有以下代码来计算数据库中的行数并将结果返回给用户：

// Connect to database and select
$mysqli = mysqli_connect($config['db_hostname'], $config['db_username'], $config['db_password'], $config['db_name']);
$mysqli->set_charset('utf8');
$select = 'SELECT COUNT(*) AS wines FROM  ft_form_4 WHERE feu_id = "'.$feuid.'"';
$response = mysqli_query($mysqli, $select) or die("Error: ".mysqli_error($mysqli));
$result = mysqli_fetch_array($response, MYSQLI_ASSOC);

$wines = (int)$result[wines];

echo $wines;

// Return 0 for no entries
if ($wines = 0) {

echo 'You currently have no wines entered, your current total entry fee is <strong>£0</strong>.';
}

elseif ($wines = 1) {

echo 'You currently have 1 wine entered, your current total entry fee is <strong>£135</strong>.';
}

elseif ($wines > 1) {

$fee = $wines * 135;
echo 'You currently have '.$wines.' wines entered, your current total entry fee is <strong>'.$fee.'</strong>.';
}

当我运行代码时，结果会在第一位（我刚刚放进去测试）中显示为3，这是正确的，但它总是显示第二行，表示输入了一瓶酒，入场费是135英镑。它似乎不认为3是一个数字。
我已经尝试了第二批使用mysqli num_行的代码，但我也没有任何运气。

最佳答案

比较错误，应该使用==而不是=