python - 我如何将这段代码放入函数中

我想将其放入函数newton（x）中，该函数允许用户在其中输入x的值。

from math import *
x=20
for iteration in range(1, 1001):

        xnew = x - (((3*10**-5)*exp((log1p(10**3/(3*10**-5)))*(1-exp(-.12*x))))-1)/(.12*(3*10**-5)*exp((log1p(10**3/(3*10**-5))))*(1-exp(-.12*x)*(-.12*x))) # the Newton-Raphson's formula
        print("Error",x-xnew," Xn:   ", xnew)
        if abs(xnew - x) < 0.000001:
            break

        x = xnew
print('The root : %0.5f' % xnew)
print('The number of iterations : %d' % iteration)

最佳答案

您可以使其成为返回2元组的函数：

from math import *

def newton(x):
    xnew = iteration = None
    for iteration in range(1, 1001):
            xnew = x - (((3*10**-5)*exp((log1p(10**3/(3*10**-5)))*(1-exp(-.12*x))))-1)/(.12*(3*10**-5)*exp((log1p(10**3/(3*10**-5))))*(1-exp(-.12*x)*(-.12*x))) # the Newton-Raphson's formula
            print("Error",x-xnew," Xn:   ", xnew)
            if abs(xnew - x) < 0.000001:
                break
            x = xnew
    return xnew, iteration

xnew, iteration = newton(20)
print('The root : %0.5f' % xnew)
print('The number of iterations : %d' % iteration)

关于python - 我如何将这段代码放入函数中，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/54680698/