编辑:在n.m.的要求下，我已包括了我正在使用的完整代码，尽管它很冗长。
我编写了一个简短的示例程序，用于研究虚拟调用的开销。
timer.h:
#include <chrono>
#include <cstdint>
class Timer {
typedef std::chrono::high_resolution_clock clock;
typedef clock::time_point time_point;
typedef clock::duration duration;
time_point begin;
time_point end;
public:
void start()
{
begin = clock::now();
}
void stop()
{
end = clock::now();
}
double as_seconds()
{
duration dur = end - begin;
return (double) dur.count() * (double) duration::period::num / (double) duration::period::den;
}
};
virtual.h:
#pragma once
static const int NUM_DERIVED = 10;
struct Base {
int val;
#ifdef NO_VIRTUAL
#define virtual
#endif
virtual void f();
virtual ~Base();
#undef virtual
};
Base *create_base(unsigned max_derived);
virtual.cpp:
#include <algorithm>
#include <iostream>
#include <memory>
#include <typeinfo>
#include <vector>
#include "virtual.h"
#include "timer.h"
template <typename Container>
void measure_call(const Container &c)
{
Timer t;
t.start();
for (auto &ptr : c) {
ptr->f();
}
t.stop();
std::cout << "Virtual calls: " << c.size() << '\n';
std::cout << "Elapsed time (s): " << t.as_seconds() << '\n';
}
int main()
{
typedef std::unique_ptr<Base> base_ptr;
typedef std::vector<base_ptr> base_vector;
const int NUM_VEC = 10000000;
const int NUM_DERIVED_USED = NUM_DERIVED;
base_vector vec1;
base_vector vec2;
Timer t;
vec1.reserve(NUM_VEC);
vec2.reserve(NUM_VEC);
for (int i = 0; i < NUM_VEC; ++i) {
Base *b1 = create_base(1);
Base *b2 = create_base(NUM_DERIVED_USED);
vec1.emplace_back(b1);
vec2.emplace_back(b2);
}
std::cout << "Measuring random vector of " << 1 << " derived classes\n";
measure_call(vec1);
std::cout << '\n';
std::cout << "Measuring random vector of " << NUM_DERIVED_USED << " derived classes\n";
measure_call(vec2);
std::cout << '\n';
std::cout << "Sorted vector of " << NUM_DERIVED << " derived clases\n";
std::sort(
vec2.begin(), vec2.end(),
[](const base_ptr &a, const base_ptr &b) -> bool
{
return typeid(*a).hash_code() < typeid(*b).hash_code();
}
);
for (int i = 0; i < 20; ++i) {
int idx = vec2.size() / 20 * i;
std::cout << "vector[" << idx << "]: " << typeid(*vec2[idx]).name() << '\n';
}
std::cout << '\n';
std::cout << "Measuring sorted vector of " << NUM_DERIVED_USED << " derived classes\n";
measure_call(vec2);
return 0;
}
virtual_impl.cpp:
#include <cstdlib>
#include "virtual.h"
template <int N>
struct Derived : Base {
void f() { Base::val = N; }
~Derived() {}
};
void Base::f() {}
Base::~Base() {}
Base *create_base(unsigned max_derived)
{
unsigned n = max_derived > NUM_DERIVED ? NUM_DERIVED : max_derived;
switch (rand() % n) {
case 9:
return new Derived<9>;
case 8:
return new Derived<8>;
case 7:
return new Derived<7>;
case 6:
return new Derived<6>;
case 5:
return new Derived<5>;
case 4:
return new Derived<4>;
case 3:
return new Derived<3>;
case 2:
return new Derived<2>;
case 1:
return new Derived<1>;
case 0:
return new Derived<0>;
default:
return nullptr;
}
}
我将virtual_impl.cpp编译到一个共享库中，以防止编译器弄乱和虚化或内联事物:
$ g++ -shared --std=c++11 -O3 virtual_impl.cpp -o libvirtual_impl.so
$ g++ --std=c++11 -O3 virtual.cpp -L. -lvirtual_impl -o virtual
$ ./virtual
我得到的结果是:
Measuring random vector of 1 derived classes
Virtual calls: 10000000
Elapsed time (s): 0.039333
Measuring random vector of 10 derived classes
Virtual calls: 10000000
Elapsed time (s): 0.089604
Sorted vector of 10 derived clases
vector[0]: 7DerivedILi8EE
vector[500000]: 7DerivedILi8EE
vector[1000000]: 7DerivedILi8EE
vector[1500000]: 7DerivedILi7EE
vector[2000000]: 7DerivedILi7EE
vector[2500000]: 7DerivedILi2EE
vector[3000000]: 7DerivedILi2EE
vector[3500000]: 7DerivedILi9EE
vector[4000000]: 7DerivedILi9EE
vector[4500000]: 7DerivedILi0EE
vector[5000000]: 7DerivedILi1EE
vector[5500000]: 7DerivedILi1EE
vector[6000000]: 7DerivedILi1EE
vector[6500000]: 7DerivedILi6EE
vector[7000000]: 7DerivedILi6EE
vector[7500000]: 7DerivedILi4EE
vector[8000000]: 7DerivedILi4EE
vector[8500000]: 7DerivedILi3EE
vector[9000000]: 7DerivedILi5EE
vector[9500000]: 7DerivedILi5EE
Measuring sorted vector of 10 derived classes
Virtual calls: 10000000
Elapsed time (s): 0.115058
如您所见，具有10个派生类的成本比仅包含一个派生类的成本高出近3倍。分支预测似乎是一个可能的目标，但是在某种程度上按类型排序的列表上，性能甚至比随机列表还要差!
EDIT2 :
在代码生成中似乎没有发生任何黑魔法。我在这里找到了
measure_call的反汇编:(gdb) disassemble
Dump of assembler code for function _Z12measure_callISt6vectorISt10unique_ptrI4BaseSt14default_deleteIS2_EESaIS5_EEEvRKT_:
0x0000000100002170: push r14
0x0000000100002172: push r13
0x0000000100002174: push r12
0x0000000100002176: mov r12,rdi
0x0000000100002179: push rbp
0x000000010000217a: push rbx
0x000000010000217b: sub rsp,0x10
0x000000010000217f: call 0x10000283e <dyld_stub__ZNSt6chrono3_V212system_clock3nowEv>
0x0000000100002184: mov rbp,QWORD PTR [r12+0x8]
0x0000000100002189: mov rbx,QWORD PTR [r12]
0x000000010000218d: mov r13,rax
0x0000000100002190: cmp rbx,rbp
0x0000000100002193: je 0x1000021b1 <_Z12measure_callISt6vectorISt10unique_ptrI4BaseSt14default_deleteIS2_EESaIS5_EEEvRKT_+65>
0x0000000100002195: nop DWORD PTR [rax+rax+0x0]
0x000000010000219a: nop WORD PTR [rax+rax+0x0]
0x00000001000021a0: mov rdi,QWORD PTR [rbx]
0x00000001000021a3: add rbx,0x8
0x00000001000021a7: mov rcx,QWORD PTR [rdi]
0x00000001000021aa: call QWORD PTR [rcx]
0x00000001000021ac: cmp rbp,rbx
0x00000001000021af: jne 0x1000021a0 <_Z12measure_callISt6vectorISt10unique_ptrI4BaseSt14default_deleteIS2_EESaIS5_EEEvRKT_+48>
0x00000001000021b1: call 0x10000283e <dyld_stub__ZNSt6chrono3_V212system_clock3nowEv>
[iostream stuff follows]
最佳答案
问题是这样的:
void f() { Base::val = N; }
还有这个:
for (auto &ptr : c) {
ptr->f();
}
按类型排序会随机分配您正在读取的内存位置(以获取vtable地址)并分配给(
Base::val)，这会使10个vtable的分支预测相形见war。