public class Learning {
int i = 1; // i is assigned to 1.
static int s = 2;// s is assigned to 2.
Learning() {
i = 0; s++; // i is assigned to 0 and s increases to 2.
System.out.println("test: " + i + s);// this line will display test: 03 since the values are above given.
}
public static void main (String [] args) {
Learning t1 = new Learning();// Creating and instance variable from the Class Learning.
System.out.println("t1: " + t1.i + t1.s);//t1 reaches with the help of the . the value of i as well as s and again this line will print out t1: 03
t1.s = 6;// Now the variable get s new value which is 6
Learning t2 = new Learning();// Creating another instance variable from the class called Learning
t2.i = 8;// Now the value for i is set for 8.
System.out.println("t2: " + t2.i + t2.s);// Now I thought the program would display t2: 86 since I have already got the value 8 and 6 assigned above, but it doesn't do that.
}
}
好的，就像上面看到的，我有了一个新的Java代码，我认为我确实理解了很多事情，至少我对我所理解的东西做过评论，并认为我的思维方式是正确的。
请放心，查看我的上述评论，如果我错了，请纠正我。
我已经测试过，上面的代码实际打印如下：
test: 03
t1: 03
test: 07
t2: 87
因此，换句话说，我是部分正确的人，我根本不明白为什么要打印测试：07，因为没有循环，为什么t2：87不是t2：86？
我最初期望的是这样的：
test: 03
t1: 03
t2: 86
任何专业人士想检查吗？
提前致谢。
最佳答案
每次创建Learning时都会调用new Learning()，因为它是Learning类所有实例的构造函数。您创建两个Learning实例，因此test被打印两次。值是87的原因是因为s是static。这意味着Learning的所有实例都为s共享相同的值。因此，将t1的s实例修改为6也会修改t2的s实例，然后在其构造函数中将其递增，并变为7。