python - Pandas为每个字符拆分数据帧列

我有多个数据帧列，如下所示：

                         Day1
0    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD
1    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD
2    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD
3    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD
4    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD

我想要的是每个角色都在一个单独的列中分开：

     012345678910111213....
0    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD
1    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD
2    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD
3    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD
4    DDDDDDDDDDBBBBBBAAAAAAAAAABBBBBBDDDDDDDDDDDDDDDD

这样，“第1天的列”被分成48列，每列都有一个值a/b/c/d
我试过分开，但没用。

最佳答案

您可以调用apply并在值的pd.Series上为每一行调用list

In [16]:

df['Day1'].apply(lambda x: pd.Series(list(x)))
Out[16]:
  0  1  2  3  4  5  6  7  8  9  ... 38 39 40 41 42 43 44 45 46 47
0  D  D  D  D  D  D  D  D  D  D ...  D  D  D  D  D  D  D  D  D  D
1  D  D  D  D  D  D  D  D  D  D ...  D  D  D  D  D  D  D  D  D  D
2  D  D  D  D  D  D  D  D  D  D ...  D  D  D  D  D  D  D  D  D  D
3  D  D  D  D  D  D  D  D  D  D ...  D  D  D  D  D  D  D  D  D  D
4  D  D  D  D  D  D  D  D  D  D ...  D  D  D  D  D  D  D  D  D  D

[5 rows x 48 columns]

似乎有尾随空格，请使用str.rstrip删除这些空格：

df['Day1'] = df['Day1'].str.rstip()

那么做上面的