我正在实现可以考虑以下junit测试的代码:
package it.unica.pr2.pizze.test;
import static org.junit.Assert.assertEquals;
import static org.junit.Assert.fail;
import static org.junit.Assert.assertTrue;
import org.junit.Test;
import org.junit.Ignore;
import org.junit.runner.RunWith;
import org.junit.runners.JUnit4;
import java.util.*;
import it.unica.pr2.pizze.*;
@RunWith(JUnit4.class)
public class TestPizza {
@Test
public void test1() {
Ingrediente mozzarella = new Ingrediente("mozzarella",50);
Ingrediente pomodoro = new Ingrediente("pomodoro",10);
Ingrediente[] ingredienti = new Ingrediente[] {mozzarella, pomodoro}
Pizza pizzaMargherita = new Pizza(ingredienti);
assertTrue( pizzaMargherita.calorie() == 60 );
List ingredientiMargherita = pizzaMargherita;
assertTrue(ingredientiMargherita.size() ==2);
assertTrue(ingredientiMargherita.get(0) == mozzarella);
assertTrue(ingredientiMargherita.get(1) == pomodoro);
}
这是我的 class :披萨
package it.unica.pr2.pizze;
import java.util.ArrayList;
import java.util.List;
public class Pizza {
private ArrayList<Ingrediente> ingredienti;
public Pizza(Ingrediente[] ing) {
this.ingredienti = new ArrayList<>();
int i = 0;
while (i < ing.length) {
this.ingredienti.add(ing[i]);
i++;
}
}
public double calorie(){
double sumaCalorie = 0;
for(Ingrediente elem: this.ingredienti)
sumaCalorie += elem.getCalorie();
return sumaCalorie;
}
}
另一类:成分
package it.unica.pr2.pizze;
public class Ingrediente {
private String nomeIngrediente;
private double calorie;
public Ingrediente(String nomeIngrediente, double calorie) throws IngredienteNonValidoException {
this.nomeIngrediente = nomeIngrediente;
if (calorie < 0) throw new IngredienteNonValidoException();
else
this.calorie = calorie;
}
public void setNomeIng(String nomeIngrediente) {
this.nomeIngrediente = nomeIngrediente;
}
public void setCalorie(double calorie) {
this.calorie = calorie;
}
public String getNomeIng() {
return this.nomeIngrediente;
}
public double getCalorie() {
return this.calorie;
}
}
运行测试后,出现以下错误:
error: incompatible types: Pizza cannot be converted to List
List ingredientiMargherita = pizzaMargherita;
因此,我不知道如何仅使用operator =将ArrayList转换为List,我无法修改junit测试代码。
最佳答案
如果您无法修改分配,则必须执行以下操作:
public class Pizza implements List {
...
}
或类似的东西
public class Pizza extends AbstractList {
...
}