r - 合并不同长度的数据帧

我想从dat2添加变量：

          concreteness familiarity typicality
amoeba            3.60        1.30       1.71
bacterium         3.82        3.48       2.13
leech             5.71        1.83       4.50

到dat1：

    ID  variable value
1    1    amoeba     0
2    2    amoeba     0
3    3    amoeba    NA
251  1 bacterium     0
252  2 bacterium     0
253  3 bacterium     0
501  1     leech     1
502  2     leech     1
503  3     leech     0

提供以下输出：

    X ID  variable value concreteness familiarity typicality
1   1  1    amoeba     0         3.60        1.30       1.71
2   2  2    amoeba     0         3.60        1.30       1.71
3   3  3    amoeba    NA         3.60        1.30       1.71
4 251  1 bacterium     0         3.82        3.48       2.13
5 252  2 bacterium     0         3.82        3.48       2.13
6 253  3 bacterium     0         3.82        3.48       2.13
7 501  1     leech     1         5.71        1.83       4.50
8 502  2     leech     1         5.71        1.83       4.50
9 503  3     leech     0         5.71        1.83       4.50

如您所见，必须将dat1中的信息复制到dat2中的多行中。

这是我失败的尝试：

dat3 <- merge(dat1, dat2, by=intersect(dat1$variable(dat1), dat2$row.names(dat2)))

出现以下错误：

Error in as.vector(y) : attempt to apply non-function

请在此处找到重复的示例：

dat1：

structure(list(ID = c(1L, 2L, 3L, 1L, 2L, 3L, 1L, 2L, 3L), variable = structure(c(1L,
1L, 1L, 2L, 2L, 2L, 3L, 3L, 3L), .Label = c("amoeba", "bacterium",
"leech", "centipede", "lizard", "tapeworm", "head lice", "maggot",
"ant", "moth", "mosquito", "earthworm", "caterpillar", "scorpion",
"snail", "spider", "grasshopper", "dust mite", "tarantula", "termite",
"bat", "wasp", "silkworm"), class = "factor"), value = c(0L,
0L, NA, 0L, 0L, 0L, 1L, 1L, 0L)), .Names = c("ID", "variable",
"value"), row.names = c(1L, 2L, 3L, 251L, 252L, 253L, 501L, 502L,
503L), class = "data.frame")

dat2：

structure(list(concreteness = c(3.6, 3.82, 5.71), familiarity = c(1.3,
3.48, 1.83), typicality = c(1.71, 2.13, 4.5)), .Names = c("concreteness",
"familiarity", "typicality"), row.names = c("amoeba", "bacterium",
"leech"), class = "data.frame")

最佳答案

您可以将连接变量添加到dat2，然后使用merge：

dat2$variable <- rownames(dat2)
merge(dat1, dat2)
   variable ID value concreteness familiarity typicality
1    amoeba  1     0         3.60        1.30       1.71
2    amoeba  2     0         3.60        1.30       1.71
3    amoeba  3    NA         3.60        1.30       1.71
4 bacterium  1     0         3.82        3.48       2.13
5 bacterium  2     0         3.82        3.48       2.13
6 bacterium  3     0         3.82        3.48       2.13
7     leech  1     1         5.71        1.83       4.50
8     leech  2     1         5.71        1.83       4.50
9     leech  3     0         5.71        1.83       4.50