python - 多次尝试，没有exec()解决方案

我有这么多次尝试

errors_log = set()
try:
    page_element = chrome.find_element_by_link_text("Next Page")
except Exception as e:
    errors_log.add(e)
try:
    page_element = chrome.find_element_by_class_name("pager_next")
except Exception as e:
    errors_log.add(e)

根据其他问题的答案，我重构了代码：

page_elements = ['chrome.find_element_by_link_text("Next Page")',
                 'chrome.find_element_by_class_name("pager_next")',]
for page_element in page_elements:
    try:
        exec(page_element)
    except Exception as e:
       errors_log.add(e)

我对此感到难过，可能是因为使用exec()

我如何重构它并不难看？



感谢Zakharov的有用回答，我将代码重构为

actions = [chrome.find_element_by_class_name,
           chrome.find_element_by_link_text]
next_pages = ["pager_next ", "Next Page"]
prev_pages = ["pager_prev ", "Prev Page"]

def get_page_element_by_multiple_tries(actions, pages):
    """
    Try different context.
    """
    for action, page in zip(actions, pages):
        try:
            page_element = action(page)
        except Exception as e:
            errors_log.add(e)
            print(e)
    # print(errors_log)
    return page_element

最佳答案

您可以将Python函数作为对象存储在列表中（因为它们是对象）并在循环中调用它们：

actions = [chrome.find_element_by_link_text, chrome.find_element_by_class_name]
pages = ["Next Page", "pager_next"]

for action, page in zip(actions, pages):
    try:
        page_element = action(page)
    except Exception as e:
        errors_log.add(e)