c++ - 用于C++的Colormap库，可将给定值转换为红色，绿色和蓝色值

我正在寻找将给定值转换为红色，绿色和蓝色值的颜色图库。与matlab [1]的颜色图功能相似。最好是在C++中。

[1] http://www.mathworks.com/help/techdoc/ref/colormap.html

最佳答案

认为对于个人图书馆来说这太简单了，我自己实现了它自己，这是C语言中的示例(您可以查看Wikipedia进行数学解释):

    /**
     * Computes the color gradiant
     * color: the output vector
     * x: the gradiant (beetween 0 and 360)
     * min and max: variation of the RGB channels (Move3D 0 -> 1)
     */
    void GroundColorMix(double* color, double x, double min, double max)
{
   /*
    * Red = 0
    * Green = 1
    * Blue = 2
    */
    double posSlope = (max-min)/60;
    double negSlope = (min-max)/60;

    if( x < 60 )
    {
        color[0] = max;
        color[1] = posSlope*x+min;
        color[2] = min;
        return;
    }
    else if ( x < 120 )
    {
        color[0] = negSlope*x+2*max+min;
        color[1] = max;
        color[2] = min;
        return;
    }
    else if ( x < 180  )
    {
        color[0] = min;
        color[1] = max;
        color[2] = posSlope*x-2*max+min;
        return;
    }
    else if ( x < 240  )
    {
        color[0] = min;
        color[1] = negSlope*x+4*max+min;
        color[2] = max;
        return;
    }
    else if ( x < 300  )
    {
        color[0] = posSlope*x-4*max+min;
        color[1] = min;
        color[2] = max;
        return;
    }
    else
    {
        color[0] = max;
        color[1] = min;
        color[2] = negSlope*x+6*max;
        return;
    }
}