我正在尝试使用qmlRegisterType扩展QML。我有一个python类-PyQml.py，main.qml文件和样板代码。
问题是我无法在main.qml文件中引用（导入）PyQml对象，但出现错误->找不到QML模块（PyQml）。
到目前为止，我已经确定了QML_IMPORT_PATH变量路径。由于是希望，我在其中一个路径中创建了一个名为PyQml.py的文件夹，其中包含PyQml.py，但仍然没有成功。此外，我在Qt Creator项目中找不到* .pro文件。我想应该为我的自定义对象添加另一个路径。
PyQml.py
class PyQml(QObject):
def __init__(self, parent=None):
super().__init__(parent)
# Initialise the value of the properties.
self._name = ''
self._shoeSize = 0
# Define the getter of the 'name' property. The C++ type of the
# property is QString which Python will convert to and from a string.
@Property('str')
def name(self):
return self._name
# Define the setter of the 'name' property.
@name.setter
def name(self, name):
self._name = name
# Define the getter of the 'shoeSize' property. The C++ type and
# Python type of the property is int.
@Property(int)
def shoeSize(self):
return self._shoeSize
# Define the setter of the 'shoeSize' property.
@shoeSize.setter
def shoeSize(self, shoeSize):
self._shoeSize = shoeSize
qmlengine.py
import sys
import sqlite3
from PySide2 import QtCore, QtGui, QtWidgets, QtQuick
from PySide2.QtCore import Qt,QUrl
from PySide2.QtQml import QQmlApplicationEngine,qmlRegisterType
from PySide2.QtGui import QGuiApplication
from ViewModel import PyQml
if __name__ == '__main__':
app = QGuiApplication(sys.argv)
engine = QQmlApplicationEngine()
print(QQmlApplicationEngine.importPathList(engine))
ctx = engine.rootContext()
ctx.setContextProperty("qmlapp", engine) #the string can be anything
qmlRegisterType(PyQml.PyQml, 'People', 1, 0, 'Person');
engine.load('Documents/ctmd/Qml/main.qml')
win = engine.rootObjects()[0]
win.show()
sys.exit(app.exec_())
main.qml
import QtQuick 2.0
import QtQuick.Controls 1.4
import PyQml 1.0 ---- Error QML module not found ( PyQml)
ApplicationWindow {
menuBar: MenuBar {
Menu {
title: "File"
MenuItem { text: "Open..." }
MenuItem { text: "Close" }
}
Menu {
title: "Edit"
MenuItem { text: "Cut" }
MenuItem { text: "Copy" }
MenuItem { text: "Paste" }
}
}
Grid {
columns: 3
spacing: 2
Rectangle { color: "red"; width: 50; height: 50 }
Rectangle { color: "green"; width: 20; height: 50 }
Rectangle { color: "blue"; width: 50; height: 20 }
Rectangle { color: "cyan"; width: 50; height: 50 }
Rectangle { color: "magenta"; width: 10; height: 10 }
}
}
项目文件夹树
Qml
-main.qml
PyQml.py
qmlengine.py
PyQml只是一个示例类，在一天结束时，我想传递我在python中计算的自定义数据（x，y坐标），并用qml绘制该数据
最佳答案
TL; DR;没有解决方案来消除错误消息，因为它是QtCreator和Qt for Python的限制。但是QtCreator只是一个IDE，因此不需要在那里工作，相反，您只需要从控制台/ CMD运行代码：
python /path/of/script.py
您遇到以下错误：
使用qmlRegisterType注册QObject时，“ People”是QML中程序包的名称，“ Person”是组件的名称，因此，除非更改注册表参数，否则不要在导入中使用PyQml。
QtCreator / QtQuickDesigner在Python支持方面仍然有局限性，因此消息：“找不到Qml模块（FooPackage）”是其中的一个示例。正如Qt for Python / PySide2的开发人员在将来的版本中指出的那样，他们将添加新功能，但目前尚无法实现。
我看到您在出版物中指定的结构与您的项目不匹配，因为例如您表示main.qml位于与qmlengine.py处于同一级别的QML文件夹中，但在负载中使用的是“ Documents / ctmd / Qml / main.qml”。
PySide2在Property装饰器及其设置器上有局限性，因为QML无法识别PySide2，而是使用了广泛的声明：
name_of_property = Property(type_of_property, fget = getter_of_property, ...)如果Qt属性带有设置器，则它必须具有关联的信号。
考虑到上述情况，解决方案是：
├── PyQml.py
├── Qml
│ └── main.qml
└── qmlengine.py
qmlengine.py
import os
import sys
from PySide2.QtCore import QUrl
from PySide2.QtGui import QGuiApplication
from PySide2.QtQml import QQmlApplicationEngine, qmlRegisterType
import PyQml
if __name__ == "__main__":
app = QGuiApplication(sys.argv)
qmlRegisterType(PyQml.PyQml, "People", 1, 0, "Person")
engine = QQmlApplicationEngine()
ctx = engine.rootContext()
ctx.setContextProperty("qmlapp", engine) # the string can be anything
current_dir = os.path.dirname(os.path.realpath(__file__))
filename = os.path.join(current_dir, "Qml/main.qml")
engine.load(QUrl.fromLocalFile(filename))
if not engine.rootObjects():
sys.exit(-1)
sys.exit(app.exec_())
PyQml.py
from PySide2.QtCore import Property, Signal, QObject
class PyQml(QObject):
nameChanged = Signal(str)
shoeSizeChanged = Signal(int)
def __init__(self, parent=None):
super().__init__(parent)
# Initialise the value of the properties.
self._name = ""
self._shoeSize = 0
# Define the getter of the 'name' property. The C++ type of the
# property is QString which Python will convert to and from a string.
def get_name(self):
return self._name
# Define the setter of the 'name' property.
def set_name(self, name):
if self._name != name:
self._name = name
self.nameChanged.emit(name)
name = Property(str, fget=get_name, fset=set_name, notify=nameChanged)
# Define the getter of the 'shoeSize' property. The C++ type and
# Python type of the property is int.
def get_shoeSize(self):
return self._shoeSize
# Define the setter of the 'shoeSize' property.
def set_shoeSize(self, shoeSize):
if self._shoeSize != shoeSize:
self._shoeSize = shoeSize
self.shoeSizeChanged.emit(shoeSize)
shoeSize = Property(
int, fget=get_shoeSize, fset=set_shoeSize, notify=shoeSizeChanged
)
main.qml
import QtQuick 2.0
import QtQuick.Controls 1.4
import People 1.0
ApplicationWindow {
visible: true
Person{
name: "foo"
shoeSize: 10
}
menuBar: MenuBar {
Menu {
title: "File"
MenuItem { text: "Open..." }
MenuItem { text: "Close" }
}
Menu {
title: "Edit"
MenuItem { text: "Cut" }
MenuItem { text: "Copy" }
MenuItem { text: "Paste" }
}
}
Grid {
columns: 3
spacing: 2
Rectangle { color: "red"; width: 50; height: 50 }
Rectangle { color: "green"; width: 20; height: 50 }
Rectangle { color: "blue"; width: 50; height: 20 }
Rectangle { color: "cyan"; width: 50; height: 50 }
Rectangle { color: "magenta"; width: 10; height: 10 }
}
}