我的嵌套列表看起来很混乱，只是更长的时间：
fruit_mess = [['watermelon,0,1.0\n'], ['apple,0,1.0\n'], ['"pineapple",0,1.0\n'], ['"strawberry, banana",0,1.0\n'], ['peach plum pear,0,1.0\n'], ['"orange, grape",0,1.0\n']]
最终，我想要看起来像这样的东西：
neat_fruit = [['watermelon',0,1.0], ['apple',0,1.0], ['pineapple',0,1.0], ['strawberry, banana',0,1.0], ['peach plum pear',0,1.0], ['orange, grape',0,1.0]]
但我不确定如何处理引号中的双引号，以及如何将果实与数字分开，尤其是用逗号分隔某些果实时。我已经尝试了很多东西，但是一切似乎都使事情变得一团糟。任何建议将不胜感激。
最佳答案
使用csv模块（在标准库中）处理名称中带有逗号的双引号水果：
import csv
import io
fruit_mess = [['watermelon,0,1.0\n'], ['apple,0,1.0\n'], ['"pineapple",0,1.0\n'], ['"strawberry, banana",0,1.0\n'], ['peach plum pear,0,1.0\n'], ['"orange, grape",0,1.0\n']]
# flatten the list of lists into a string:
data='\n'.join(item[0].strip() for item in fruit_mess)
reader=csv.reader(io.BytesIO(data))
neat_fruit=[[fruit,int(num1),float(num2)] for fruit,num1,num2 in reader]
print(neat_fruit)
# [['watermelon', 0, 1.0], ['apple', 0, 1.0], ['pineapple', 0, 1.0], ['strawberry, banana', 0, 1.0], ['peach plum pear', 0, 1.0], ['orange, grape', 0, 1.0]]
关于python - 清理嵌套列表，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/6762529/