我想根据其行名为列表中的每个数据框创建一个列年份。关于此问题has been asked before,但不幸的是答案无济于事。那么,有办法吗?

mylist <- list(structure(list(a = 1:10), .Names = "a", row.names = 1991:2000, class = "data.frame"),
            structure(list(a = 1:10), .Names = "a", row.names = 1992:2001, class = "data.frame"))


预期结果:

[[1]]
      a year
1991  1 1991
1992  2 1992
1993  3 1993
1994  4 1994
1995  5 1995
1996  6 1996
1997  7 1997
1998  8 1998
1999  9 1999
2000 10 2000

[[2]]
      a year
1992  1 1992
1993  2 1993
1994  3 1994
1995  4 1995
1996  5 1996
1997  6 1997
1998  7 1998
1999  8 1999
2000  9 2000
2001 10 2001

最佳答案

我们可以使用Map

Map(cbind, mylist, year= lapply(mylist, rownames))

08-19 23:50