我有以下带有以下代码的数据集,该代码在ggplot2中生成所需的图形。我想按组在x轴上标记PTID,以便它显示ptid的显示方式以及它们所在的组。

     PTID      Group    variable   value
1   subject1    Group 1  Bio.V3.B   43
2   subject2    Group 1  Bio.V3.B   7410
3   subject3    Group 2  Bio.V3.B   13227
4   subject4    Group 2  Bio.V3.B   4832
5   subject5    Group 3  Bio.V3.B   205
6   subject6    Group 3  Bio.V3.B   24899
1   subject1    Group 1  Bio.V3.C   496
2   subject2    Group 1  Bio.V3.C   5932
3   subject3    Group 2  Bio.V3.C   24093
4   subject4    Group 2  Bio.V3.C   85
5   subject5    Group 3  Bio.V3.C   9503
6   subject6    Group 3  Bio.V3.C   18249

ggplot(data=meltedwk28v3, aes(x=PTID, y=value, fill=variable)) +
    geom_bar(width= .5, colour="black", stat="identity",  #barwidth
             position=position_dodge(width=.7),  #gapwidth
             size=.2) +                        # Thinner lines
    scale_fill_hue(name="Bio-V3 Clade") +      # Set legend title
    xlab("PTID") + ylab("MFI") + # Set axis labels
    ggtitle("Wk28 Bio-V3 MFI") +  # Set title
    theme_classic() + theme(axis.text.x = element_text(angle=90,     hjust=0, vjust=0)) #Themes


谢谢!

最佳答案

一种可能性是将“ PTID”和“组”之间的interaction用作x变量:

ggplot(data = df, aes(x = interaction(PTID, Group, sep = " "), y = value, fill = variable)) +
  geom_bar(width= 0.5, colour="black", stat = "identity",
           position = position_dodge(width = 0.7),
           size = 0.2) +
  xlab("PTID") + ylab("MFI") +
  ggtitle("Wk28 Bio-V3 MFI") +
  theme_classic() +
  theme(axis.text.x = element_text(angle = 90, hjust = 0, vjust = 0))

关于r - 按组标记X轴值,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/27891049/

10-12 17:12