我正在开发金融应用程序,需要计算IRR (in-built functionality of Excel),并在C here中找到了如此出色的教程,在C# here中找到了此类答案。

我实现了上面的C语言代码,但是当IRR为正数时,它会给出完美的结果。当它应该返回负值时,它不会返回。而在Excel中,=IRR(values,guessrate)对于某些值也返回负IRR。

我在上面的C#链接中也提到了代码,似乎它遵循良好的过程并返回错误,并且还希望它也返回负IRR,与Excel相同。但是我不熟悉C#,因此无法在Objective-C或C中实现相同的代码。

我正在从上面的链接中编写C代码,该代码已实现以帮助您。

#define LOW_RATE 0.01
#define HIGH_RATE 0.5
#define MAX_ITERATION 1000
#define PRECISION_REQ 0.00000001
double computeIRR(double cf[], int numOfFlows)
{
    int i = 0, j = 0;
    double m = 0.0;
    double old = 0.00;
    double new = 0.00;
    double oldguessRate = LOW_RATE;
    double newguessRate = LOW_RATE;
    double guessRate = LOW_RATE;
    double lowGuessRate = LOW_RATE;
    double highGuessRate = HIGH_RATE;
    double npv = 0.0;
    double denom = 0.0;
    for (i=0; i<MAX_ITERATION; i++)
    {
        npv = 0.00;
        for (j=0; j<numOfFlows; j++)
        {
            denom = pow((1 + guessRate),j);
            npv = npv + (cf[j]/denom);
        }

        /* Stop checking once the required precision is achieved */
        if ((npv > 0) && (npv < PRECISION_REQ))
            break;
        if (old == 0)
            old = npv;
        else
            old = new;
        new = npv;
        if (i > 0)
        {
            if (old < new)
            {
                if (old < 0 && new < 0)
                    highGuessRate = newguessRate;
                else
                    lowGuessRate = newguessRate;
            }
            else
            {
                if (old > 0 && new > 0)
                    lowGuessRate = newguessRate;
                else
                    highGuessRate = newguessRate;
                }
        }
        oldguessRate = guessRate;
        guessRate = (lowGuessRate + highGuessRate) / 2;
        newguessRate = guessRate;
    }
    return guessRate;
}

我已将结果附加了一些值,这些值在Excel和上面的C语言代码中是不同的。
 Values:             Output of Excel: -33.5%
 1 = -18.5,          Output of C code: 0.010 or say (1.0%)
 2 =  -18.5,
 3 = -18.5,
 4 = -18.5,
 5 = -18.5,
 6 =  32.0

Guess rate: 0.1

最佳答案

由于low_rate和high_rate均为正,因此您无法获得负分数。您必须更改:

#define LOW_RATE 0.01

例如
#define LOW_RATE -0.5

10-05 21:26