我想根据Neo4j中的相关性排序返回的数据。
出于我的目的,可以将相关性简化为“我要搜索的单词的索引”,其中索引越低,相关性越高。
例
我有以下三个节点:
node : {
Label: PROD
properties : {
name: "Bearing replacement Skateboard"
}
}
node : {
Label: PROD
properties : {
name: "Skateboard"
}
}
node : {
Label: PROD
properties : {
name: "L7 Skateboard"
}
}
我希望他们以以下顺序退回:
node : {
Label: PROD
properties : {
name: "Skateboard" // name.indexOf("Skateboard") = 0
}
}
node : {
Label: PROD
properties : {
name: "L7 Skateboard" // name.indexOf("Skateboard") = 3
}
}
node : {
Label: PROD
properties : {
name: "Bearing replacement Skateboard" // name.indexOf("Skateboard") = 19
}
}
到目前为止,我有:
String query = "MATCH (n:PROD) where LOWER(n.name) CONTAINS LOWER({textToSearch}) RETURN n ORDER BY LOWER(n.name) ASC LIMIT 15";
String textToSearch = "Skateboard";
Map<String, Object> queryParams = new HashMap<>();
queryParams.put("textToSearch", textToSearch);
try (
Transaction ignored = database.beginTx();
Result resultSet = database.execute(query, queryParams)
) {
Iterator<Node> results = resultSet.columnAs("n");
while (results.hasNext()) {
Node node = results.next();
/* data processing here */
}
}
这只是按名称排序结果。有没有办法告诉neo4j根据
n.name.indexOf({textToFind})
进行排序? 最佳答案
在Cypher中做这样的事情怎么样
MATCH (n:PROD)
WHERE n.name_lc CONTAINS toLower({textToSearch})
WITH n, SPLIT(n.name_lc, toLower({textToSearch})) as parts
RETURN n.name, SIZE(parts[0]) AS leading
ORDER BY leading
为了有效利用以上...
在属性的小写版本上创建索引
CREATE INDEX ON :PROD(name_lc)
将常规名称复制为小写版本
MATCH (n:PPOD)
SET n.name_lc = toLower(n.name)
关于java - Neo4j-按相关性排序,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/44250810/